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09 Dec 2024, 01:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
54% (02:30) correct
46%
(02:18)
wrong
based on 223
sessions
History
Date
Time
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Not Attempted Yet
Avisail and Barry drove from Columbus to Des Moines by different routes, each of which was longer than 900 miles, and neither exceeded the speed limit of 60 miles per hour at any time during their journeys. If they left Columbus at the same time, did Avisail arrive in Des Moines before Barry?
(1) The distance Avisail traveled was 120 miles greater than the distance Barry traveled.
(2) Avisail’s average speed for his trip was 10 miles per hour greater than Barry’s average speed for his trip.
(1) The distance Avisail traveled was 120 miles greater than the distance Barry traveled.
(2) Avisail’s average speed for his trip was 10 miles per hour greater than Barry’s average speed for his trip.
22 Dec 2024, 03:39
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Avisail and Barry drove from Columbus to Des Moines by different routes, each of which was longer than 900 miles, and neither exceeded the speed limit of 60 miles per hour at any time during their journeys. If they left Columbus at the same time, did Avisail arrive in Des Moines before Barry?
(1) The distance Avisail traveled was 120 miles greater than the distance Barry traveled.
d_A = d_B + 120
(2) Avisail’s average speed for his trip was 10 miles per hour greater than Barry’s average speed for his trip
s_A = s_B + 10
Avisail's time: t_A = (d_B + 120) / (s_B + 10)
Barry's time: t_B = d_B / s_B
To determine if Avisail arrived first, compare t_A and t_B:
(t_A < t_B) becomes:
(d_B + 120) / (s_B + 10) < d_B / s_B
Cross-multiply:
(d_B + 120) * s_B < d_B * (s_B + 10)
Simplify:
120 * s_B < 10 * d_B
12 * s_B < d_B (Avisail arrived first if this inequality is satisfied)
Given s_B<60 so 12*s_B(max)< 12*60= 720
But it is also given that distance>900
Therefore 12 * s_B < d_B (Is not possible hence inequality not satisfied)
Answer-C
(1) The distance Avisail traveled was 120 miles greater than the distance Barry traveled.
d_A = d_B + 120
(2) Avisail’s average speed for his trip was 10 miles per hour greater than Barry’s average speed for his trip
s_A = s_B + 10
Avisail's time: t_A = (d_B + 120) / (s_B + 10)
Barry's time: t_B = d_B / s_B
To determine if Avisail arrived first, compare t_A and t_B:
(t_A < t_B) becomes:
(d_B + 120) / (s_B + 10) < d_B / s_B
Cross-multiply:
(d_B + 120) * s_B < d_B * (s_B + 10)
Simplify:
120 * s_B < 10 * d_B
12 * s_B < d_B (Avisail arrived first if this inequality is satisfied)
Given s_B<60 so 12*s_B(max)< 12*60= 720
But it is also given that distance>900
Therefore 12 * s_B < d_B (Is not possible hence inequality not satisfied)
Answer-C
General Discussion
09 Dec 2024, 12:47
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don't know what is correct option for only statment 1 is correct,, but here
answer should be statment 1 alone is sufficient to answer the question but statement 2 alone is not sufficient to ans the question
answer should be statment 1 alone is sufficient to answer the question but statement 2 alone is not sufficient to ans the question
