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sahil770

A 12-kilogram fertilizer blend contains 40 percent nitrogen and 60 percent phosphorus, by weight.

To create a 12-kilogram mixture that contains 55 percent nitrogen and 45 percent phosphorus, how many kilograms of the original blend should be removed and replaced with pure nitrogen?

Original mixture: -
Nitrogen = 40%*12 = 4.8 kg
Phosphorus = 60%*12 = 7.2 kg
Total = 12 kg

Let x kg of mixture be removed and replaced with pure nitrogen.

Desired mixture: -
Nitrogen = 4.8 - 40%x + x = 4.8 + .6x = 55%*12 = 6.6 kg
Phosphorus = 7.2 - 60%x = 7.2 - .6x = 45%*12 = 5.4 kg

4.8 + .6x = 6.6
.6x = 1.8
x = 3 kg

IMO C
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sahil770
A 12-kilogram fertilizer blend contains 40 percent nitrogen and 60 percent phosphorus, by weight. To create a 12-kilogram mixture that contains 55 percent nitrogen and 45 percent phosphorus, how many kilograms of the original blend should be removed and replaced with pure nitrogen?
A. 2.8
B. 4
C. 3
D. 2.9
E. 2.5
Since total weight is 12 kg,
Nitrogen = 4.8 kg
Phosphorous = 7.2 kg

After new percentages,
Nitrogen = 6.6 kg
Phosphorous = 5.4 kg

whatever Nitrogen will be removed will be in the ratio of 40/100

4.8 - 04.x + x = 6.6
x = 3
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This can be solved using alligation

original solution contains 40%, to be mixed with a solution containing 100% with a desired outcome of 55%.

40% ---- 55% ---- 100%
----- 15%------45%-----

solution should be 3 parts 40% to 1 part 100%.

Therefore 25% of the current solution should be removed (3kg) ans: C

sahil770
A 12-kilogram fertilizer blend contains 40 percent nitrogen and 60 percent phosphorus, by weight. To create a 12-kilogram mixture that contains 55 percent nitrogen and 45 percent phosphorus, how many kilograms of the original blend should be removed and replaced with pure nitrogen?
A. 2.8
B. 4
C. 3
D. 2.9
E. 2.5
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