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siddhantvarma
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Hey Rohit,

I am using the original equation -> 3 \((a-b)^2\) + \(5b^2\) = 48

(1) When \(b^2\) = 0

3 \((a-b)^2\) + 0 = 48

=> \((a-b)^2\) = 16

(2) When \(b^2\) = 9

3 \((a-b)^2\) + 45 = 48

=> \((a-b)^2\) = 1

Hope this helps.

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Harsha
Rohit_842
HarshavardhanR

How did you get (a-b)^2 values as 16, 1 and so on

HarshavardhanR


Above is one way to solve this question

One important inference for me was that b has to be a 3-multiple here, given the integer constraints. We can use this information to figure out the possible values of "a" and "b" as shown. We can keep iterating till we arrive at a value of "a" that is in the options. Here the second iteration with \(b^2\) = 9 gave us "2" as a possible "a" value. Which is choice E.

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siddhantvarma
If a and b are integers, and if \(3( a − b )^2 + 5b^2 = 48\) , which of the following could be the value of a ?

(A) - 1
(B) 0
(C) 1
(D) 3
(E) 2
Sharing a quick solution, let me know if you guys see any caveats in this --

Both (3(a-b)^2) and (5b^2) are either even or odd. Since their sum 48 is even, they must have the same parity.

That forces (b) and (a-b) to be either both even or both odd - in either case (a) is even. So only (a=0) or (a=2) are possible from the list.

Test (a=0): 3b^2+5b^2=8b^2=48 => b^2=6 --- not an integer.

So Answer = 2
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