F = number of falcons
H = number of hawks
O = number of owls
Owls = 1/3 more than hawks
So,
O=H+1/3H=4/3H
Hawks = 3/7 fewer than falcons
So,
H=F−3/7F=4/7F
Now plug value of HHH into OOO's formula:
O=4/3*4/7F=16/21F
Now total birds =
F+H+O=F+4/7F+16/21F
Let’s combine them:
F=21/21F
4/7F=12/21F
16/21F
Add them:
(21+12+16)/21F=49/21F
We want the smallest total, so we want the smallest value of F such that
49/21F
So FFF must be a multiple of 21.
Smallest such positive number = 21.
If F=21F = 21F=21
H=4/7*21=12
O=4/3*12=16
total =F+H+O=21+12+16=49
ANS 49
Bunuel
A wildlife center houses 1/3 more owls than hawks, and 3/7 fewer hawks than falcons. If the center has at least one of each bird, what is the smallest possible total number of falcons, hawks, and owls it could have?
A. 28
B. 36
C. 42
D. 45
E. 49