Last visit was: 19 Nov 2025, 04:04

It is currently 19 Nov 2025, 04:04

Toolkit

Practice Tests

Quantitative Questions

Problem Solving (PS)

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more

Request Expert Reply

Confirm Cancel

Nov 20
UCR MBA Impact - Live Q&A with UCR AdCom & Student
07:30 AM PST
-
08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 22
GMAT RC Masterclass
11:00 AM IST
-
01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
Nov 23
Conquer Algebra on the GMAT Focus Edition
11:00 AM IST
-
01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Nov 25
Try OnDemand GMAT Masterclass
10:00 AM EST
-
11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.

Back to Forum

Create Topic

GMAT Club Olympics 2025 (Day 10): A wildlife center houses 1/3 more

1 2 3 4 5

HarshaBujji

Joined: 29 Jun 2020

Last visit: 16 Nov 2025

Posts: 695

Own Kudos:

885

[1]

Given Kudos: 247

Location: India

Products:

Posts: 695

Kudos: 885

[1]

11 Jul 2025, 23:56

Kudos

Bookmarks

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

Let's assume falcons, owls, and hawks are in f,o & h numbers.

This is a typical word-based problem. The important thing is converting this into an equation.

Hawks are 3/7 fewer than falcons: h =4/7f.

Similarly, Owls are 1/3 more than hawks: o =4/3h.

So o = 16/21f. Total = 49f/21.

As we know, all the birds are in intergal numbers. f has to be 3, 21. We need to not just look at the total but also the individual bird count.
To make owl a natural number, f has to be 21. No other choice.

Hence total birds is possible if f= 21,42,... Smallest of all occurs when f=21.

Hence total is 49. IMO E

DyutiB

Joined: 21 Jul 2024

Last visit: 19 Nov 2025

Posts: 25

Own Kudos:

[1]

Given Kudos: 3

Products:

Posts: 25

Kudos: 16

[1]

12 Jul 2025, 00:04

Kudos

Bookmarks

A wildlife center houses 1/3 more owls than hawks, and 3/7 fewer hawks than falcons. If the center has at least one of each bird, what is the smallest possible total number of falcons, hawks, and owls it could have?

A. 28
B. 36
C. 42
D. 45
E. 49

owls = (1+1/3) of hawks = 4/3 of hawks
hawks = (1-3/7) of falcons = 4/7 of falcons

So for the smallest possible total number of birds, we have to get the smallest possible multiple of 3 and 7 i.e. 21 as no. of birds has to be an integer.

So smallest possible falcons = 21
so smallest possible hawks = 12
so the smallest possible owls = 16

So smallest possible total = 49

Answer: (E)

DungThuy

Joined: 18 Dec 2024

Last visit: 11 Nov 2025

Posts: 10

Own Kudos:

Given Kudos: 5

Posts: 10

Kudos: 9

12 Jul 2025, 00:05

Kudos

Bookmarks

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

From the problem:

1/3 more owls than hawks
→ Owls = H+1/3*H=4/3*H
→ So: O=4/3*H => H = 3/4*O
3/7 fewer hawks than falcons
→ Hawks = F−3/7*F=4/7*F
→ So: H=4/7*F => F = 7/4*H = 21/16*O
So, the total number: O + H + F = O + 3/4*O + 21/16*O = 49/16*O
=> Total number min = 49

sanjitscorps18

Joined: 26 Jan 2019

Last visit: 19 Nov 2025

Posts: 637

Own Kudos:

623

[1]

Given Kudos: 128

Location: India

Schools: IMD'26

Products:

Schools: IMD'26

Posts: 637

Kudos: 623

[1]

12 Jul 2025, 00:48

Kudos

Bookmarks

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

Hawks = h
Owls = 4h/3
Falcons = f

Now h = 4f/7
Hence, falcons must be divisible by 7

and
f = 7h/4
Hence, hawks must be divisible by 4

=> Owls = 4/3 * 4f/7 = 16f/21
Now falcons must be divisible by 21 to make owls an integer

Total birds = f + 16f/21 + 4f/7 = 49f/21

Basis the denominators, let's try f = 21, then
h = 4*21/7 = 12
and
Owls = 16*21/21 = 16

Total birds = 16 + 12 + 21 = 49

Option E

Ryga

Joined: 12 Aug 2023

Last visit: 19 Aug 2025

Posts: 68

Own Kudos:

Given Kudos: 5

Location: India

Concentration: General Management, Leadership

Schools: INSEAD Jan '26 NUS '27 Stern '26

GMAT Focus 1: 695 Q90 V80 DI83 Verified score

Schools: INSEAD Jan '26 NUS '27 Stern '26

GMAT Focus 1: 695 Q90 V80 DI83 Verified score

Posts: 68

Kudos: 51

12 Jul 2025, 01:12

Kudos

Bookmarks

Let falcons = F
→ Hawks = (4/7)F
→ Owls = (4/3) × (4/7)F = (16/21)F
Total = F + (4/7)F + (16/21)F = (49/21)F
→ To make total an integer, F must be divisible by 21
→ Smallest F = 21

Then:
Hawks = (4/7)×21 = 12
Owls = (4/3)×12 = 16
Total = 21 + 12 + 16 = 49

asingh22

Joined: 31 Jul 2024

Last visit: 18 Nov 2025

Posts: 68

Own Kudos:

[1]

Given Kudos: 8

Location: India

Schools: Foster '26 (II) Goizueta '26 (S) Scheller '26 Anderson '26 Darden '26 Kelley '26 Kellogg '26 Ross '26 Sloan '26 UNC '26 (S) Stern '26 Yale '26 Haas '26 Owen '26 (II)

GMAT Focus 1: 635 Q84 V78 DI82 Verified score

GMAT Focus 2: 655 Q89 V80 DI78 Verified score

GPA: 2.5

Products:

Schools: Foster '26 (II) Goizueta '26 (S) Scheller '26 Anderson '26 Darden '26 Kelley '26 Kellogg '26 Ross '26 Sloan '26 UNC '26 (S) Stern '26 Yale '26 Haas '26 Owen '26 (II)

GMAT Focus 2: 655 Q89 V80 DI78 Verified score

Posts: 68

Kudos: 57

[1]

12 Jul 2025, 01:13

Kudos

Bookmarks

lets' say Falcons = x,
hawks ( 3/7 fewer ) = 4/7 X
and owls 1/3 more than hawks = (4/7)X + (1/3)(4/7)X = 16/21 x

Total A = X +(4/7)X +(16/21) x = 49/21 X = 7/3 X

X = 3/7 A

out of all options 28 and 49 are multiples of 7, then A can be 28 or 49

let's try with 28, then X = 12, hawks = (4/7)*12 = it's not an integer, Not valid

Let's try with 49, x = 21, hawks = (4/7)*21 = 12 and owls = (16/21)*21 =16

And 49

dragobreathfire

Joined: 05 Jul 2025

Last visit: 14 Aug 2025

Posts: 34

Own Kudos:

[1]

Given Kudos: 24

Location: India

Schools: Kellogg '26 Booth '26 HBS '26

GPA: 7.5

Schools: Kellogg '26 Booth '26 HBS '26

Posts: 34

Kudos: 17

[1]

12 Jul 2025, 03:02

Kudos

Bookmarks

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

IMO E is correct.

It is written than, centre has 1/3 more owl than hawks. So, O = h + (1/3)h = 4h/3

Simillarly it is given that it has 3/7 fewer hawks than falcons , So, h = f-(3/7)f = 4f/7

Now, lets say h is 1, then ration of proportion of birds h : o : f will become;

1:4/3:7/4

now when we just multiple each with 12 then, lowest non fraction number will be,

12:16:21

So, total birds will become 49.

Mardee

Joined: 22 Nov 2022

Last visit: 16 Oct 2025

Posts: 127

Own Kudos:

110

[1]

Given Kudos: 17

Products:

Posts: 127

Kudos: 110

[1]

12 Jul 2025, 03:15

Kudos

Bookmarks

Owls = 1/3 more than hawks
Hawks = 3/7 fewer than falcons

Let the number of hawks = x
Let the number of falcons= y
Let the number of owls = z

We know that,
Owls = 1/3 more than hawks
=> z = x + x/3 = 4x/3

Hawks = 3/7 fewer than falcons
=> x = y - 3y/7 = 4y/7

=> z = 4x/3 = 4*4y/3*7 = 16y/21

Now total birds = y + x + z = y + 4y/7 + 16y/21 = 49y/21

Since birds need to be a whole number and small in count, lets multiple it with the smallest number possible which is divisible with the denominator i.e
Let y = 21
=> x = 4*21/7 = 12
=> z = 16*21/21 = 16

=> Total number of birds = 49

E. 49

Punt

Joined: 09 Jul 2024

Last visit: 11 Nov 2025

Posts: 36

Own Kudos:

[1]

Given Kudos: 15

Location: India

Posts: 36

Kudos: 29

[1]

12 Jul 2025, 03:21

Kudos

Bookmarks

Given,
A wildlife centre house has ,
Number of Owls = O
Number of Hawks = H
Number of Falcons = F
O = H + H/3 = 4H/3
H = F – 3F/7 = 4F/7
To find
If the center has at least one of each bird, what is the smallest possible total number of falcons, hawks, and owls it could have?

Solution:
O in terms of F,
O = 4H/3
= 4(4F/7) */3
= 16F/21
Total Birds = O + H + F
= 16F/21 + 4F/7 + F
= 49F/21
As 49 & 21 are co-prime. For smallest possible number of total birds, the number F shall be multiple of 21.
So, check for F= 21,
H = 4F/7 = 4 (21)/7 = 12
O = 4H/3 = 4 (12)/3 = 16

T = 16 + 12 + 21 = 49

Ans: E

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

UfuomaOh

Joined: 14 Sep 2023

Last visit: 17 Nov 2025

Posts: 83

Own Kudos:

[1]

Given Kudos: 14

Products:

Posts: 83

Kudos: 50

[1]

12 Jul 2025, 03:40

Kudos

Bookmarks

A wildlife center houses 1/3 more owls than hawks, and 3/7 fewer hawks than falcons. If the center has at least one of each bird, what is the smallest possible total number of falcons, hawks, and owls it could have?

This is an LCM question

Hawks=H
Owls=O
Falcons= F

O=1/3+H
O=4/3H

H=F-3/7
H=4/7F

In terms of F
O= 4/3*(4/7F)
O=16/21F

T=(F+4/7F+16/21F)
T=49/21F
If T is an integer, the smallest number F can be is 21

T=49

Rahilgaur

Joined: 24 Jun 2024

Last visit: 19 Nov 2025

Posts: 104

Own Kudos:

[1]

Given Kudos: 45

GMAT Focus 1: 575 Q81 V82 DI72 Verified score

Products:

GMAT Focus 1: 575 Q81 V82 DI72 Verified score

Posts: 104

Kudos: 74

[1]

12 Jul 2025, 03:55

Kudos

Bookmarks

Bunuel

Lets consider number of falcons = x
hawks = x-3x/7 = 4x/7
Owls = 4x/7 + 4x/21 = 16x/21

Total number of birds = falcons, hawks, and owls = x + 4x/7 +16x/21
= (21x + 12x + 16x)/ 21 = 49x/21

the minimum integer possible for 49x/21, x must be 21
hence, Total number of birds = 49. E

ODST117

Joined: 15 Aug 2024

Last visit: 29 Oct 2025

Posts: 173

Own Kudos:

[1]

Given Kudos: 149

Posts: 173

Kudos: 85

[1]

12 Jul 2025, 04:09

Kudos

Bookmarks

$O=H+\frac{1}{3}H = \frac{4}{3}H$

$H=F-\frac{3}{7}F=\frac{4}{7}F$

$O=\frac{4}{3}(\frac{4}{7}F)=\frac{16}{21}F$

We need to minimize $F+H+O$.
The number of Owls and Hawks are dependent on the number of Falcons. If we minimize $F$, we can minimize $F+H+O$.

We know $O=\frac{16}{21}F$

For $F$ to be an integer, it needs to be a multiple of $21$. The smallest multiple of $21$ is $21$.

When $F=21$
$H=12$ and $O=16$

$\\
F+H+O=21+12+16=49\\
\\
$

shaliny

Joined: 30 Oct 2023

Last visit: 24 Oct 2025

Posts: 99

Own Kudos:

Given Kudos: 712

Products:

Posts: 99

Kudos: 26

12 Jul 2025, 04:17

Kudos

Bookmarks

According to question, ratio would be - F : O : H
7 : 4 : 3
so sum of the ratio = 14
means minimum possible multiple of 14 would be the smallest possible numbers of F, O and H. in the options 28 is the smallest multiple of 14 so this is the answer.
option A

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

MinhChau789

Joined: 18 Aug 2023

Last visit: 17 Nov 2025

Posts: 132

Own Kudos:

140

[1]

Given Kudos: 2

Posts: 132

Kudos: 140

[1]

12 Jul 2025, 04:17

Kudos

Bookmarks

We know that O/H = 4/3; H/F = 4/7
So O/F = 16/21

Assume F = 21, O = 16, then H = 12. O:H:F = 16:12:21 and can't be reduced further. So smallest total birds = 49.

Answer: E

jkkamau

Joined: 25 May 2020

Last visit: 19 Nov 2025

Posts: 132

Own Kudos:

107

[1]

Given Kudos: 122

Location: Kenya

Schools: Haas '25

GMAT 1: 730 Q50 V46 Verified score

GPA: 3.5

Products:

Schools: Haas '25

GMAT 1: 730 Q50 V46 Verified score

Posts: 132

Kudos: 107

[1]

12 Jul 2025, 04:31

Kudos

Bookmarks

Let Owls be O, Hawks be H and Falcons be F
H = 1-3/7F = 4/7F
O = 4/3X4/7 =16/21F
Total = (4/7+16/21+1)F= 49/21F.
To minimize the total lets assume F=21 meaning O=16 and H=12 so total minimum is 21+16+12= 49
ANS E

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

GarvitGoel

Joined: 06 Aug 2024

Last visit: 17 Nov 2025

Posts: 69

Own Kudos:

Posts: 69

Kudos: 54

12 Jul 2025, 05:13

Kudos

Bookmarks

Option E is the correct answer.

Lets understand the information mentioned in the passage before trying to solve for it.

So the question starts by telling us that "A wildlife center houses 1/3 more owls than hawks, and 3/7 fewer hawks than falcons. If the center has at least one of each bird". Then asks us the minimum possible total number of falcons, hawks, and owls.

So as per the question, Owl = (1+1/3)Hawks => Owl = (4/3)Hawks,
Hawks = (1-3/7)Falcons => Hawks = (4/7)Falcons
=>From the above information we can conclude that, Owl = (4/3)Hawks => Owl = (4/3)*(4/7)Falcons => Owl = (16/21)Falcons

Now we need to find the minimum possible value of all the available birds:
=>Owl + Hawk + Falcon
=>(16/21)Falcon + (4/7)Falcon + Falcon
=>(28/21)Falcon + Falcon
=>(49/21)Falcon

Now we have used up all the available information from the question. So lets try putting the above value in the options and see which one of them gives us our answer.

Option A: Total = 28
=> (49/21)Falcon = 28
=> Falcon = 12
Now, Hawk = (4/7)Falcon => Hawk = (4/7)*12, This will give us the answer in decimal form and we know that number of Hawk can not be in decimal. Eliminated

Option B: Total = 36
=> (49/21)Falcon = 36
=> Falcon = 108/7, This will give us the answer in decimal form. Eliminated

Option C: Total = 42
=> (49/21)Falcon = 42
=> Falcon = 18
Now, Hawk = (4/7)Falcon => Hawk = (4/7)*18, This will give us the answer in decimal form and we know that number of Hawk can not be in decimal. Eliminated

Option D: Total = 45
=> (49/21)Falcon = 45
=> Falcon = 135/7, This will give us the answer in decimal form. Eliminated

Option E: Total = 49
=> (49/21)Falcon = 49
=> Falcon = 21
Now, Hawk = (4/7)Falcon => Hawk = (4/7)*21 => Hawk = 12
Owl = (4/3)Hawk => Owl = (4/3)*12 => Owl = 16

So after checking and solving all options we can now conclude that only Only E gives us the correct answer.

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

adityaprateek15

Joined: 26 May 2023

Last visit: 19 Nov 2025

Posts: 268

Own Kudos:

104

[1]

Given Kudos: 309

Location: India

Schools: Ross '26 Tepper '26 McCombs '26

GPA: 2.7

Products:

Schools: Ross '26 Tepper '26 McCombs '26

Posts: 268

Kudos: 104

[1]

12 Jul 2025, 05:15

Kudos

Bookmarks

Given,
Owls (O) = (1+1/3)Hawks(H) = 4H/3

H = [1-(3/7)] Falcon(F) = 4F/7

F = 7H/4

Q: Min possible value of O+H+F?

Min(4H/3+H+7H/4)

Since, H should be an integer, Min value will be LCM(3,4) = 12

If H = 12,
F = 21
O = 16

Total = 49

Option E

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

twinkle2311

Joined: 05 Nov 2021

Last visit: 18 Nov 2025

Posts: 150

Own Kudos:

167

[1]

Given Kudos: 10

Location: India

Concentration: Finance, Real Estate

Schools: ISB '26 Wharton '26

GPA: 9.041

Schools: ISB '26 Wharton '26

Posts: 150

Kudos: 167

[1]

12 Jul 2025, 05:26

Kudos

Bookmarks

O = H + (1/3)*H = (4/3)H
H = F − (3/7)*F = (4/7)F
F must be a multiple of 7 for H to be whole and H must be a multiple of 3 for O to be whole
Let F be 7k, then H = 4k and and O = 16/3k
Now, let's say k = 3m then
F = 21m ; H = 12m ; O = 16m
To get the smallest possible number, let's use m = 1
F + H + O = 21 + 12 + 16 = 49.
Answer: E

missionmba2025

Joined: 07 May 2023

Last visit: 07 Sep 2025

Posts: 341

Own Kudos:

427

[1]

Given Kudos: 52

Location: India

Posts: 341

Kudos: 427

[1]

12 Jul 2025, 05:48

Kudos

Bookmarks

Bunuel

This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

Option E is my answer

Show Spoiler

Attachment:

GMAT-Club-Forum-sfk2xxsu.jpeg [ 79.73 KiB | Viewed 126 times ]

Lemniscate

Joined: 28 Jun 2025

Last visit: 09 Nov 2025

Posts: 80

Own Kudos:

[1]

Posts: 80

Kudos: 72

[1]

12 Jul 2025, 05:56

Kudos

Bookmarks

Owls are 1/3 more than Hawks : (4/3)*Hawks
Hawks are 3/7 fewer Falcons : (4/7)*Falcons

Owls are (4/3)*(4/7)*Falcons = (16/21)*Falcons

Falcons must be at least 21. Check if the other values become integers too:
If Falcons=21 then Owls=16
If Owls=16 then Hawks=(3/4)*Owls=12

Owls=16, Hawks=12, Falcons=21

16+12+21=49

Answer E

1 2 3 4 5

Moderators:

Bunuel

Math Expert

105379 posts

Krunaal

Tuck School Moderator

805 posts

Prep Toolkit

Announcements

How the UC Riverside MBA Helps You Thrive Personally & Professionally

Thursday, Nov 20, 2025
10:30am NY / 3:30pm London / 9pm Mumbai

Master in Management, Finance, Business Analytics and more Master’s Programs!

Live Profile Evaluation Chat Session with ARINGO

Wednesday, November 19, 2025
09:00 am PDT | 10:30 pm IST
Location: GMAT Club Chat

Top GMAT Focus Debriefs

GMAT Club Olympics 2025 (Day 10): A wildlife center houses 1/3 more

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Problem Solving (PS) Questions

GMAT Club Olympics 2025 (Day 10): A wildlife center houses 1/3 more

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards