The total population is 5 people (P,Q,R,S,T).
Set A: Triplets (3 people, same parents)
Set B: Twins (2 people, same parents)
Step 1: Evaluate Statement (1)
P, Q, and R all have the same biological parents.
This statement identifies a "parental cluster" of three people.
Possibility Alpha: P, Q, and R are the triplets.
Possibility Beta: All five people (P, Q, R, S, T) are siblings from the same parents. In this scenario, P could be one of the twins, and Q and R could be two of the triplets. They would still all share the same parents.
Conclusion: Because we don't know if the twins and triplets are siblings to each other, we can't be sure if P is a triplet or a twin.
Insufficient.Step 2: Evaluate Statement (2)
P, S, and T do not all have the same biological parents.
This statement is a "negative" clue. It tells us that the five people are not all siblings.
It proves that the Triplets and the Twins come from two different sets of parents.
However, it doesn't tell us which group P belongs to. P could be a twin whose parents are different from the triplets S and T. Or P could be a triplet whose parents are different from the twins S and T.
Insufficient.Step 3: Combining the Statements
We now have two vital pieces of information:
The Triplets and Twins have different parents (from Statement 2).
P, Q, and R share the same parents (from Statement 1).
If the Triplets and Twins have different parents, there is only one group of people in this set of five that can share parents: the Triplets. Since P, Q, and R share parents, they must be the Triplets. If P were a twin, he could only share parents with one other person (his twin), not two others (Q and R), because Statement 2 ruled out the possibility of the two groups being siblings.
Hence,
Triplets = {P, Q, R}
Twins = {S, T}
P is a triplet.
So, the answer is C (Both statements together are sufficient)