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24 Dec 2025, 07:22
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At 0 hours,
Hermione's couldron : 27 = 3^3
Ron's couldron: 729 = 3^6
Every 6 hours Hermoine's couldren becomes 3 times and after every 18 hors ron's couldron becomes 9 times
at 30th hour, Hermione's couldren becomes: 3^3 * 3^5
After 30th hour, Ron's couldron becomes: 3^6 * 3^2
Answer: C
Hermione's couldron : 27 = 3^3
Ron's couldron: 729 = 3^6
Every 6 hours Hermoine's couldren becomes 3 times and after every 18 hors ron's couldron becomes 9 times
at 30th hour, Hermione's couldren becomes: 3^3 * 3^5
After 30th hour, Ron's couldron becomes: 3^6 * 3^2
Answer: C
24 Dec 2025, 07:28
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Hermoine starts with 27, increases by 200% every 6 hours, triples every 6 hours.
After t hours, H(t) = (3^3)*(3^(t/6)) = 3^(3+(t/6))
Ron starts with 729 , increases by 800% every 18 hours, becomes 9 times every 18 hours
After t hours,R(t) = (3^6)*(9^(t/18)) = 3^(6+(t/9))
To find the time at which both numbers will be equal
3 + (t/6) = 6 + (t/9)
54 + 3t = 108 + 2t
t = 54
After t hours, H(t) = (3^3)*(3^(t/6)) = 3^(3+(t/6))
Ron starts with 729 , increases by 800% every 18 hours, becomes 9 times every 18 hours
After t hours,R(t) = (3^6)*(9^(t/18)) = 3^(6+(t/9))
To find the time at which both numbers will be equal
3 + (t/6) = 6 + (t/9)
54 + 3t = 108 + 2t
t = 54
Bunuel
24 Dec 2025, 07:34
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Hermione
Starts with 27
Every 6 hours , increases by 200%
200 % increase = 2x
H = 27 x 3^(no of 6 hour periods)
Ron = 729 x 9 ^(no of 18 hour period)
Writing both in the same base
H = 3^3 x 3^t/6= 3^3+t/6
R= 3^6 x (3^2)^t/18= 3^6+t/9
Equating them
3+t/6 = 6+t/9
54+3t= 108 +2t
t = 54
Starts with 27
Every 6 hours , increases by 200%
200 % increase = 2x
H = 27 x 3^(no of 6 hour periods)
Ron = 729 x 9 ^(no of 18 hour period)
Writing both in the same base
H = 3^3 x 3^t/6= 3^3+t/6
R= 3^6 x (3^2)^t/18= 3^6+t/9
Equating them
3+t/6 = 6+t/9
54+3t= 108 +2t
t = 54
