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23 Dec 2025, 09:00
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Alex Total: 240
Afternoon Total: 180
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
67% (02:44) correct
33%
(03:19)
wrong
based on 141
sessions
History
Date
Time
Result
Not Attempted Yet
A team composed of Alex and Maya sold souvenir booklets at two performances of a local orchestra on the same day: one performance took place in the afternoon and the other took place in the evening. Each booklet sold for $4 at the afternoon performance and $6 at the evening performance. Alex sold twice as many booklets in the afternoon performance as Maya sold in the evening performance, and Maya sold half as many booklets in the afternoon performance as Alex sold in the evening performance. Altogether, the team earned $1,800 from booklet sales that day.
In the table, select for Alex Total the total number of booklets Alex sold that day and select for Afternoon Total the total number of booklets the team sold at the afternoon performance that would be jointly consistent with the given information. Make only two selections, one in each column.
I31-32
| Alex Total | Afternoon Total | |
| 120 | ||
| 180 | ||
| 240 | ||
| 260 | ||
| 300 |
ShowHide Answer
Official Answer
Alex Total: 240
Afternoon Total: 180
23 Dec 2025, 10:00
Kudos
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A team composed of Alex and Maya sold souvenir booklets at two performances of a local orchestra on the same day: one performance took place in the afternoon and the other took place in the evening. Each booklet sold for $4 at the afternoon performance and $6 at the evening performance. Alex sold twice as many booklets in the afternoon performance as Maya sold in the evening performance, and Maya sold half as many booklets in the afternoon performance as Alex sold in the evening performance. Altogether, the team earned $1,800 from booklet sales that day.
In the table, select for Alex Total the total number of booklets Alex sold that day and select for Afternoon Total the total number of booklets the team sold at the afternoon performance that would be jointly consistent with the given information. Make only two selections, one in each column.
Let:
a = Alex's afternoon sales
b = Alex's evening sales
c = Maya's afternoon sales
d = Maya's evening sales
Given:
a = 2d
c = b/2, so b = 2c.
Total revenue:
4(a + c) + 6(b + d) = 1800
Substitute:
4(2d + c) + 6(2c + d) = 1800
7d + 8c = 900
• The total number of booklets Alex sold that day = a + b = 2d + 2c = 2(d + c)
• The total number of booklets the team sold on the afternoon = a + c = 2d + c
Now, let's test the options and verify against 7d + 8c = 900.
• If Alex Total is 120, then 2(d + c) = 120, which give d + c = 60. Multiply by 8: 8d + 8c = 480. Subtract 7d + 8c = 900 from it to get d = -420. Since d cannot be negative, discard this option for Alex Total.
• If Alex Total is 180, then 2(d + c) = 180, which give d + c = 90. Multiply by 8: 8d + 8c = 720. Subtract 7d + 8c = 900 from it to get d = -180. Since d cannot be negative, discard this option for Alex Total.
• If Alex Total is 240, then 2(d + c) = 240, which give d + c = 120. Multiply by 8: 8d + 8c = 960. Subtract 7d + 8c = 900 from it to get d = 60. Then, from d + c = 120, we get c = 60. This fits!
Thus:
• The total number of booklets Alex sold that day = a + b = 2d + 2c = 2(d + c) = 240.
• The total number of booklets the team sold on the afternoon = a + c = 2d + c = 180.
GMAT-Club-Forum-xcqqnpik.png [ 13.19 KiB | Viewed 1337 times ]
In the table, select for Alex Total the total number of booklets Alex sold that day and select for Afternoon Total the total number of booklets the team sold at the afternoon performance that would be jointly consistent with the given information. Make only two selections, one in each column.
GMAT Club Official Explanation:
Let:
a = Alex's afternoon sales
b = Alex's evening sales
c = Maya's afternoon sales
d = Maya's evening sales
Given:
a = 2d
c = b/2, so b = 2c.
Total revenue:
4(a + c) + 6(b + d) = 1800
Substitute:
4(2d + c) + 6(2c + d) = 1800
7d + 8c = 900
• The total number of booklets Alex sold that day = a + b = 2d + 2c = 2(d + c)
• The total number of booklets the team sold on the afternoon = a + c = 2d + c
Now, let's test the options and verify against 7d + 8c = 900.
• If Alex Total is 120, then 2(d + c) = 120, which give d + c = 60. Multiply by 8: 8d + 8c = 480. Subtract 7d + 8c = 900 from it to get d = -420. Since d cannot be negative, discard this option for Alex Total.
• If Alex Total is 180, then 2(d + c) = 180, which give d + c = 90. Multiply by 8: 8d + 8c = 720. Subtract 7d + 8c = 900 from it to get d = -180. Since d cannot be negative, discard this option for Alex Total.
• If Alex Total is 240, then 2(d + c) = 240, which give d + c = 120. Multiply by 8: 8d + 8c = 960. Subtract 7d + 8c = 900 from it to get d = 60. Then, from d + c = 120, we get c = 60. This fits!
Thus:
• The total number of booklets Alex sold that day = a + b = 2d + 2c = 2(d + c) = 240.
• The total number of booklets the team sold on the afternoon = a + c = 2d + c = 180.
Attachment:
GMAT-Club-Forum-xcqqnpik.png [ 13.19 KiB | Viewed 1337 times ]
General Discussion
23 Dec 2025, 09:47
Kudos
Bookmarks
Alex total=240
afternoon total=180
by creatin algebric equation
8x+12y+4y+6x=1800
2x=alex qty sold in afternoon
2y= alex qty sold in evening
y=maya qty sold in afternoon
like this we can solve
afternoon total=180
by creatin algebric equation
8x+12y+4y+6x=1800
2x=alex qty sold in afternoon
2y= alex qty sold in evening
y=maya qty sold in afternoon
like this we can solve
