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Updated on: 06 Mar 2026, 19:31
Originally posted by MartyMurray on 17 Feb 2026, 00:40.
Last edited by MartyMurray on 06 Mar 2026, 19:31, edited 1 time in total.
Last edited by MartyMurray on 06 Mar 2026, 19:31, edited 1 time in total.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
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Question Stats:
62% (02:29) correct
38%
(02:49)
wrong
based on 95
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If a man who weighs \(175\) pounds with \(20\) percent of his weight coming from body fat, by changing only the amount of fat in his body, changes his body composition so that \(12\frac{1}{2}\) percent of his weight comes from body fat, how much will his remaining body fat weigh in pounds?
(A) \(13\frac{1}{8}\)
(B) \(17\frac{1}{2}\)
(C) \(20\)
(D) \(21\frac{7}{8}\)
(E) \(35\)
Source: Marty Murray Coaching
(A) \(13\frac{1}{8}\)
(B) \(17\frac{1}{2}\)
(C) \(20\)
(D) \(21\frac{7}{8}\)
(E) \(35\)
Source: Marty Murray Coaching
Updated on: 23 Feb 2026, 22:29
Originally posted by MartyMurray on 17 Feb 2026, 07:27.
Last edited by MartyMurray on 23 Feb 2026, 22:29, edited 2 times in total.
Last edited by MartyMurray on 23 Feb 2026, 22:29, edited 2 times in total.
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If a man who weighs \(175\) pounds with \(20\) percent of his weight coming from body fat, by changing only the amount of fat in his body, changes his body composition so that \(12\frac{1}{2}\) percent of his weight comes from body fat, how much will his remaining body fat weigh in pounds?
In answering this question, it's key to notice that the weight of the man's remaining body fat will not be \(12\frac{1}{2}\) percent of \(175\), which is \(21\frac{7}{8}\). After all, since he changed his body composition by changing "only the amount of fat in his body," he must have reduced his weight.
So, \(12\frac{1}{2}\) percent of his weight will be a number smaller than \(21\frac{7}{8}\) since it will be \(12\frac{1}{2}\) percent of a total weight lower than \(175\) pounds.
To calculate exactly the weight of the man's remaining body fat we can proceed as follows.
Original Total Weight: \(175\)
Percent Body Fat: \(20\)
Weight of Body Fat: \(175 × 0.20 = 35\)
Weight of Body Other Than Fat: \(175 - 35 = 140\)
\(0.125 = \frac{1}{8}\)
So, \(\frac{1}{8}\) of the man's new weight comes from fat.
Thus, \(140 = \frac{7}{8}\) of the man's new total weight.
\(\frac{140}{7} = \frac{1}{8}\) of total weight \(= 20 =\) weight of remaining fat
(A) \(13\frac{1}{8}\)
(B) \(17\frac{1}{2}\)
(C) \(20\)
(D) \(21\frac{7}{8}\)
(E) \(35\)
Correct answer: C
In answering this question, it's key to notice that the weight of the man's remaining body fat will not be \(12\frac{1}{2}\) percent of \(175\), which is \(21\frac{7}{8}\). After all, since he changed his body composition by changing "only the amount of fat in his body," he must have reduced his weight.
So, \(12\frac{1}{2}\) percent of his weight will be a number smaller than \(21\frac{7}{8}\) since it will be \(12\frac{1}{2}\) percent of a total weight lower than \(175\) pounds.
To calculate exactly the weight of the man's remaining body fat we can proceed as follows.
Original Total Weight: \(175\)
Percent Body Fat: \(20\)
Weight of Body Fat: \(175 × 0.20 = 35\)
Weight of Body Other Than Fat: \(175 - 35 = 140\)
\(0.125 = \frac{1}{8}\)
So, \(\frac{1}{8}\) of the man's new weight comes from fat.
Thus, \(140 = \frac{7}{8}\) of the man's new total weight.
\(\frac{140}{7} = \frac{1}{8}\) of total weight \(= 20 =\) weight of remaining fat
(A) \(13\frac{1}{8}\)
(B) \(17\frac{1}{2}\)
(C) \(20\)
(D) \(21\frac{7}{8}\)
(E) \(35\)
Correct answer: C
Fisayofalana
Posts: 51
18 Feb 2026, 15:35
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I answered like a mixture problem. 35-x/175-x = .125.
Solving for this, you get x=15. They asked for the remaining body fat, so I subtracted 15 from 35.
The answer is 20.
Solving for this, you get x=15. They asked for the remaining body fat, so I subtracted 15 from 35.
The answer is 20.
