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each side of square ABCD has length 1, the length of line Segment CE is 1, and the length of line segment BE is equal to the length Of line segment DE. What is the area of the triangular region BCE? a. 1/3 b. (2^-2 )/4 c. 1/2 d. (2^-2)/2 e. 3/4
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line segment BC = line segment DC BE=DE(given) and CE is common between triangles CDE and BCE.so they are similar. = <DCE = <BCE = 45 or point E lies on the diagonal.
emailsector, gmat isn't testing knowledge of trigonometric formulas, so there is always other ways to get a right answer. I'm also getting 1/2sqrt2 = sqrt2/4, but it isn't among answer choices for b = 2^-2/4 = 1/16, which is impossible. So, I think there is a mistake in the answer choices.
My solwing way: from E draw a perpendicular line to BC and call it EF. Angle EFC = 90, FCE = 45 = FEC. So, with given EC = 1 we get EF = 1/sqrt2 (45:45:90 => 1:1:sqrt2). Area of EFC = 1/2 x 1 x 1/sqrt2 = 1/2sqrt2 = sqrt2/4.
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