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vivektripathi
if -2=<x=<2 and 3<=y<=8, which of the following represents the range of all possible values of y-x?
(A) 5<=y-x<=6
(B) 1<=y-x<=5
(C) 1<=y-x<=6
(D) 1<=y-x<=10
(E) 1<=y-x<=10

possible range of (y-x) is the difference between min (y-x) and max (y-x).

min (y-x) = deduct minimum x value from max y value = 3 - 2 = 1
max (y-x) = deduct minimum x value from max y value = 8 - (-2) = 10

1 =< (y - x) <= 10
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A. By subtracting 2 ineq from 1

For my experience, don't use subtraction between 2 inequalities as you probably get the wrong sign

also dont use multiplication, division , esp you don't know if the variables are negative or positive or fraction

Use addition instead

-2=<x=<2
-2 <= -x <= 2
+
3<=y<=8

3 - 2 <= y - x <= 8+2
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-2 <= X <= 2 ------(1)

3 <= y <= 8 --------(2)


Multiplying eq (1) by -1

2<= -x <=-2 -------(3)


Adding (1) & (3)

5<= y-x<=10

:-D
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Maximum value of y-x= 8 - (-2)= 10
Minimum value of y-x= 3-2= 1

E mentions the correct range :)
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vivektripathi
If -2<= x <= 2 and 3 <= y <= 8, which of the following represents the range of all possible values of y-x?

(A) 5 <= y-x <= 6
(B) 1 <= y-x <= 5
(C) 1 <= y-x <= 6
(D) 5 <= y-x <= 10
(E) 1 <= y-x <= 10
"Range of all possible values" for \(y - x\) is just another way of asking about the expression's minimum value and maximum value.

Minimum and maximum of \(y - x\)? Where

\(-2 \leq x \leq 2\)

\(3 \leq y \leq 8\)

To find the smallest (minimum) value for \(y - x\), you can either:

1) Keep order of subtraction in mind, and find two same-sign values that are close together (which omits -2 from calculation). Two positives for y, one for x. Closest: 3 and 2. Answer is 1. Or

2) Test all four cases

8 - 2 = 6
8 - (-2) = 10
3 - 2 = 1
3 - (-2) = 5

Minimum value of \(y - x\) = 1

Maximum?

1. Same things to keep in mind, but look for opposite-sign values that are large (or larger, if there are two negs. or two positives). Negative subtracted from positive = addition. Larger positive for y is 8. Only negative for x is -2. Answer is 10. Or

2. Test four cases

8 - 2 = 6
8 - (-2) = 10
3 - 2 = 1
3 - (-2) = 5

Maximum value of \(y - x\) = 10

Answer: \(1 \leq(y -x) \leq10\)

I tested all eight cases, checked my work, and time was well under a minute (so maybe what looks like the longest way isn't).

Answer E
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vivektripathi
If -2<= x <= 2 and 3 <= y <= 8, which of the following represents the range of all possible values of y-x?

(A) 5 <= y-x <= 6
(B) 1 <= y-x <= 5
(C) 1 <= y-x <= 6
(D) 5 <= y-x <= 10
(E) 1 <= y-x <= 10

The largest value of y - x is 8 - (-2) = 8 + 2 = 10.

The smallest value of y - x is 3 - 2 = 1.

Thus, 1 ≤ y - x ≤ 10.

Answer: E
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