Two men X and Y started working for a certain company at similar jobs

Question

Two men X and Y started working for a certain company at similar jobs on January 1, 1950. X asked for an initial salary of $300 with an annual increment of $30. Y asked for an initial salary of $200 with a raise of $15 every six months. Assume that the arrangements remained unaltered till December 31, 1959. Salary is paid on the last day of the month. What is the total amount paid to them as salary during the period?

A. $93,300
B. $93,200
C. $93,175
D. $93,150
E. $93,100

A. $93,300
B. $93,200
C. $93,175
D. $93,150
E. $93,100

TestPrepUnlimited · Answer

We are totaling 10 years of salary for each person, since X has an increase every year, we can group the monthly salaries into annual ones to have:

$3600 base salary, increased by $360 each year.

His salary for the last year would be  3600 + 360*9 , the mean and median of each year's salaries would be  \frac{3600 + 3600 + 360*9 }{ 2} = 3600 + 180*9 = 3600 + 1620 = 5220 . Finally multiply by 10 since that is the average for 10 years, to get  52,200 .

For Y we repeat the same steps but we can consider 20 periods of 6 months, hence base salary 1200 with increments of 90.

At the end of 10 years his salary would be  1200 + 90*19 . The mean and median of these 20 salaries would be  \frac{1200 + 1200 + 90*19}{2} . Multiply by 20 to get  24000 + 900*19 = 24000 + 17100 = 41,100 .

Finally, add both salaries to get 93,300.

Ans: A

andreagonzalez2k · Answer

I did not read it well...

LaveenaPanchal · Answer

Salary of X = 300x 12 + 330 x 12 .... upto 10 terms
= 12 (300+330+360... upto 10 terms)

Sum of salaries of x for 10 years = 12 x (2(First term) x (n-1)difference) x n/2 = 12 x(2(300) + (10-1)30)x 10/2
 = 12 x 870 x 10 /2 = 60 x 870 = 52200

Salary of Y = 200 x 6 + 215 x 6 --- upto 20 terms
= 6 ( 200 +215 + ... upto 20 terms)

Sum of Salaries of Y for 10 years = 6 x (2(First term) x (n-1)difference) x n/2 = 6 x(2(200) + (20-1)15)x 20/2
 = 6 x 685 x 20 /2 = 60 x 685 = 41100

Total salary of X & Y = 52200 + 41100 = 93300

rsrighosh · Answer

Why are we multiplying by 12 for X and 6 for Y. I do not see anywhere in the question 300$/month or 200$/month

Or am I missing something?

LaveenaPanchal · Answer

Question stem mentions salary is paid on the last dqy of the month. It means the salary figures are monthly

Posted from my mobile device

andreagonzalez2k · Answer

I did the same mistake. In my country when we talk about salary, it is supposed to be annual. Another question I saw yesterday also talked about fett and inches in a measurement problem (1 feet = 12 inches). I think some questions are too much US lozalized and should be thought a little more to international people.

AnkithaSrinivas · Answer

annual hike for X
where as bi annual hike for Y

finisher009 · Answer

X (yearly raise):

Avg salary over 10 years = (first + last)/2 = (300 + 570)/2 = 435
Total = 435 × 12 months × 10 yrs = 52,200

Y (half-yearly raise):

Avg salary over 20 half-years = (200 + 485)/2 = 342.5
Total = 342.5 × 6 months × 20 = 41,100

Sum = 93,300

Two men X and Y started working for a certain company at similar jobs

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Two men X and Y started working for a certain company at similar jobs

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