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26 Mar 2008, 06:41
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Unusual GMATPrep Geometry problem...
In the xy-plane, at what two points does the graph y = (x+a)(x+b) intersect the x axis?
1) a+b = -1
2) The graphc intersects the y-axis at (0,-6)
In the xy-plane, at what two points does the graph y = (x+a)(x+b) intersect the x axis?
1) a+b = -1
2) The graphc intersects the y-axis at (0,-6)
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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26 Mar 2008, 07:21
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jimmyjamesdonkey
Graph intersects x axis at (-a,0) and (-b,0)
Thus, if we can find a and b, then problems can be solved
1) a+b=-1 - insufficient because there are many combinations where a+b=-1
2) if graph intersects at (0,-6) then substitute into equation, we get ab=-6 - insufficient cuz we don't exactly know what would be a and b
combined statements:
a = -b-1 = -(b+1)
ab = -6
-(b+1)(b) = -6
(b^2+b) = 6
b^2+b = 6
b^2+b-6 = 0
(b+3)(b-2) = 0
b = -3,2
a = -(b+1) = 2,-3
Thus, from combined statements, we can conclude that two intersection points are (3,0) and (-2,0)
I'd answer c
please correct me if there's any mistake
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
