A farmer plants only five different kinds of vegetables - beans, corn, kale, peas, and squash. Every year the farmer plants exactly three kinds of vegetables according to the following restrictions: If the
farmer plants corn, the farmer also plants beans that year. If the
farmer plants kale one year, the farmer does not plant it the next year. In any year, the
farmer plants no more than one of the vegetables the farmer planted in the previous year.
Which of the following is a possible sequence of combinations for the farmer to plant in two successive years?
(A) Beans, corn, kale; corn, peas, squash
(B) Beans, corn, peas; beans, corn, squash
(C) Beans, peas, squash; beans, corn, kale
(D) Corn, peas, squash; beans, kale, peas
(E) Kale, peas, squash; beans, corn, kale
The three conditions are highlighted. We have beans, corn and kale.
Corn and beans come together but not beans and corn. Finally, no two vegetables continue to be same next year.
So from beans, corn and kale, kale is not grown next year as it is grown in alternate years. Hence, from beans and corn, corn can't be planted as beans would then need to be planted, thus violating one of the conditions. Therefore, beans can be planted in 2nd year. Along with beans, peas and squash can be planted in 2nd year. This leaves us with C only.
Kale can't be planted in 2nd year, so E is gone. D is gone since beans are not there in 1st year itself. A is gone for beans is not there even when corn is there. B is plain wrong for repeating two plants for two years.
Answer C.