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sachinrelan
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TheLordCommander
Bunuel, in mgmat tells us that the number of times a parabola touches the x axis can be figured out calucating the value of b^2-4ac for any equation in the form of ax^2+bx+c. can that concept be applied for the equaiton of this question - x^2-x^3? Let me know your thoughts, thank you.

No, this is a discriminant formula which can only be applied to the quadratic equations.
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The answer is 2 because of the following:

Manipulate the equation --> y = (x^2) - (x^3) --> y = (x^2)(1-x)

We then set y = 0 to find where the x-intercepts are --> 0 = (x^2)(1-x) --> This means that x intercepts are 0 and 1.

Thus C is the correct answer.
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I have a question Bunuel

So, I too got x=0,1 when y=0. So doesn't this mean 0,0 is origin. So technically, it intersects X only at 1 right ?
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I have a question Bunuel

So, I too got x=0,1 when y=0. So doesn't this mean 0,0 is origin. So technically, it intersects X only at 1 right ?

No. (0, 0) is the origin but how does this change the answer? Doesn't (0, 0) also belongs to x-axis?
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