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u0422811
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Company A has 13 employees, 8 of whom belong to the union. If 5 people Updated on: 08 Jul 2015, 01:55
Originally posted by u0422811 on 29 Sep 2010, 21:30.
Last edited by Bunuel on 08 Jul 2015, 01:55, edited 1 time in total.
Renamed the topic and edited the question.
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75% (hard)

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54% (02:12) correct 46% (02:10) wrong based on 208 sessions

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Company A has 13 employees, 8 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?

(A) 56
(B) 231
(C) 336
(D) 350
(E) 406
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E
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Company A has 13 employees, 8 of whom belong to the union. If 5 people 29 Sep 2010, 21:48
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u0422811
Company A is twice the size of its nearest competitor, Company B. Company A has 13 employees, 8 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?

(a) 56
(b) 231
(c) 336
(d) 350
(e) 406
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Looks easy: -- 8C4*5C1 + 8C5 -- 406 (E).
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Company A has 13 employees, 8 of whom belong to the union. If 5 people 30 Sep 2010, 02:08
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ezhilkumarank
u0422811
Company A is twice the size of its nearest competitor, Company B. Company A has 13 employees, 8 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?

(a) 56
(b) 231
(c) 336
(d) 350
(e) 406

Looks easy: -- 8C4*5C1 + 8C5 -- 406 (E).
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Could you please explain how you got 8c5.I used this logic...Totally 13 employees out of which 8 are union emp.In order to have atleast 4union employees in any shift.I splitted it as 8c4*5c1(selecting 4 emp from 8 union emp and 1 employee from remaining 5 non-union employees).I got the answer as 350.I didnot understand how you got 8c5.Kindly help me.
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Company A has 13 employees, 8 of whom belong to the union. If 5 people 30 Sep 2010, 02:23
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ezhilkumarank
u0422811
Company A is twice the size of its nearest competitor, Company B. Company A has 13 employees, 8 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?

(a) 56
(b) 231
(c) 336
(d) 350
(e) 406

Looks easy: -- 8C4*5C1 + 8C5 -- 406 (E).

Could you please explain how you got 8c5.I used this logic...Totally 13 employees out of which 8 are union emp.In order to have atleast 4union employees in any shift.I splitted it as 8c4*5c1(selecting 4 emp from 8 union emp and 1 employee from remaining 5 non-union employees).I got the answer as 350.I didnot understand how you got 8c5.Kindly help me.
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There are total of 13 employees, 8 of whom belong to the union and 5 doesn't. Out of 5 people working a shift at least 4 must belong to the union.

Now, at lest 4 out of 5 means that 4 or all 5 employees must belong to the union:
Out of 5 people working a shift 4 employees belong to the union and 1 doesn't: \(C^4_8*C^1_5=350\);
Out of 5 people working a shift all 5 employees belong to the union: \(C^5_8=56\);

Total # of ways: \(350+56=406\).

Answer: E.

Hope it's clear.
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Company A has 13 employees, 8 of whom belong to the union. If 5 people 07 Jul 2015, 22:52
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u0422811
Company A is twice the size of its nearest competitor, Company B. Company A has 13 employees, 8 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?

(a) 56
(b) 231
(c) 336
(d) 350
(e) 406
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Hi Bunuel,

The opening sentence to this prompt has absolutely no bearing on the actual question that is asked. I have to assume that it was originally included by accident - since the Official GMAT would not include this type of 'filler', can you remove that initial sentence?

GMAT assassins aren't born, they're made,
Rich
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Company A has 13 employees, 8 of whom belong to the union. If 5 people 20 Mar 2016, 08:06
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Company A has 13 employees, 8 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?

Total combinations= 4 from 8 union * 1 from 5 rest + 5 from 8 union
=8C4*5C1 + 8C5
= 350+56
=406
Hence E
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Company A has 13 employees, 8 of whom belong to the union. If 5 people 24 Dec 2023, 01:07
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