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09 Nov 2010, 13:07
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
46% (02:51) correct
54%
(03:04)
wrong
based on 129
sessions
History
Date
Time
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Not Attempted Yet
Two cars, Car1 and Car2 move towards each other from X and Y respectively with respective speeds of 20 m/s and 15 m/s. After meeting each other Car1 reaches Y in 10 seconds. In how many seconds does Car 2 reach X starting from Y?
A) 15.5 sec
B) 8.4 sec
C) 33.6 sec
D) 31.11 sec
E) 16.8 sec
A) 15.5 sec
B) 8.4 sec
C) 33.6 sec
D) 31.11 sec
E) 16.8 sec
09 Nov 2010, 14:24
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X--------------------------------------|----------------------------Y
Car A(20mps)------------------------->P<---------------Car B(15mps)
Let 2 cars meet each other at point P in t seconds.
Car1 covers distance= 20t. Car2 covers distance=15t. So, total distance XY= 35t.
From P, Car 1 reaches onto Y in 10 secs. So it covers 15t further.
so, 15t/20 = 10
So t=40/3 sec and total distance = (35*40)/3
Hence Car2 will cover total distance in (35*40)/(3*15) = 31.11 sec approx.
Answer D
Car A(20mps)------------------------->P<---------------Car B(15mps)
Let 2 cars meet each other at point P in t seconds.
Car1 covers distance= 20t. Car2 covers distance=15t. So, total distance XY= 35t.
From P, Car 1 reaches onto Y in 10 secs. So it covers 15t further.
so, 15t/20 = 10
So t=40/3 sec and total distance = (35*40)/3
Hence Car2 will cover total distance in (35*40)/(3*15) = 31.11 sec approx.
Answer D
09 Nov 2010, 19:37
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cleetus
Slight Variation on the above approach:
____________M_________
X Y
Car 1 Car 2
20 m/s---> <---15 m/s
Speed of Car1 : Speed of Car2 = 4:3 so distance they will cover in same time will be 4:3.
So XM: MY = 4:3
When Car 1 reaches M, it takes 10 secs to reach Y so MY = 20*10 = 200 m
Then XM = 800/3 m
Then XY = 800/3 + 200 = 1400/3 m
Car 2 takes 1400/3*15 = 31.1 sec
