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19 Dec 2011, 12:16
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A bag contains 30 tickets, numbered from ‘1’ to ‘30’. Five tickets are drawn at random and arranged in ascending order. Find the probability that the third number is 20.
The answer to this is 285/5278.. Am not convinced with the solution.Any thoughts..?
The answer to this is 285/5278.. Am not convinced with the solution.Any thoughts..?
19 Dec 2011, 12:41
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devinawilliam83
ways of selecting 5 outta 30 =30C5
let the tickets be 20,a,b,c,d
arranging them in ascending order will look like : a,b,20,c,d
a,b has to lie within 1 to 19 = 19C2
c,d has to lie within 21 to 30 = 10C2
So,
(19C2*10C2)/30C5
Please check the answer...
19 Dec 2011, 23:13
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both of your answer yield .05
