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26 Feb 2012, 06:30
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:21) correct
19%
(01:46)
wrong
based on 400
sessions
History
Date
Time
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Not Attempted Yet
If x and y are positive integers and 21x=12y what is the least possible value of xy?
(A) 14
(B) 28
(C) 63
(D) 84
(E) 252
(A) 14
(B) 28
(C) 63
(D) 84
(E) 252
26 Feb 2012, 06:34
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tom09b
\(21x=12y\) --> \(\frac{x}{y}=\frac{12}{21}=\frac{4}{7}\). Now, since x and y are positive integers then the least value of x is 4 and the least value of y is 7 --> \(xy=4*7=28\).
Answer: B.
26 Feb 2012, 06:37
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tom09b
B....
21x=12y
=> x/y = 4/7
=> 7x=4y
7(3)=4(3) => x*y=9 But it is not given
7(4)=4(7) => x*y=28
