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Bunuel
shivanigs
Hi,

Request your help to understand the concept behind the following question :

If 5 < x < 10 and y = x + 5,what is the greatest possible integer value of x + y?

Please read and follow: 11-rules-for-posting-133935.html Pay attention to the points #3, 7 and 8.

Original question is below:

If 5 < x < 10 and y = x + 5, what is the greatest possible integer value of x + y ?

A. 18
B. 20
C. 23
D. 24
E. 25

Since \(y=x+5\) then \(x+y=x+(x+5)=2x+5\). So, we need to find the greatest possible integer value of \(2x+5\).

Multiply \(5 < x < 10\) by 2: \(10<2x<20\). Now add 5 to each part of the inequality: \(15<2x+5<25\). As you can see the greatest possible integer value of \(2x+5\) is 24.

Answer: D.

Hope it's clear.

Dear Bunuel,
1.)can't understand what is the need to take 2x+5? wont it be easy to calculate with x less than 10.?
2.) when x is not integer but x+y to be integer - we can take x=9.5 and y = 14.5 - giving 24 - is this right?
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Bunuel
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Hi,

Request your help to understand the concept behind the following question :

If 5 < x < 10 and y = x + 5,what is the greatest possible integer value of x + y?

Please read and follow: 11-rules-for-posting-133935.html Pay attention to the points #3, 7 and 8.

Original question is below:

If 5 < x < 10 and y = x + 5, what is the greatest possible integer value of x + y ?

A. 18
B. 20
C. 23
D. 24
E. 25

Since \(y=x+5\) then \(x+y=x+(x+5)=2x+5\). So, we need to find the greatest possible integer value of \(2x+5\).

Multiply \(5 < x < 10\) by 2: \(10<2x<20\). Now add 5 to each part of the inequality: \(15<2x+5<25\). As you can see the greatest possible integer value of \(2x+5\) is 24.

Answer: D.

Hope it's clear.

Dear Bunuel,
1.)can't understand what is the need to take 2x+5? wont it be easy to calculate with x less than 10.?
2.) when x is not integer but x+y to be integer - we can take x=9.5 and y = 14.5 - giving 24 - is this right?

What do you mean by "need"? One can solve a question with different approaches and you can choose the approach you personally find easier.
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Dear Bunuel,

Apologies for the wrongful post..did not know the rules.Have gone thru the same,will not happen again.Thanks for your help!

Regards
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Dear Bunuel,
sorry for the word 'need'. i just only wanted to know whether the way i did is right.
thanx for the reply.
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kashishh
Dear Bunuel,
sorry for the word 'need'. i just only wanted to know whether the way i did is right.
thanx for the reply.

Yes, the way you solved is totally OK.
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The question asks what is the greatest integer value of 2X+5, where 5<X<10, the greatest value of 2X which is integer will be achieved if X=9.5

Hence the greatest integer value of X+Y = 2x9.5+5=24, answer - D
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I am getting it 23.

x = { 6,7,8,9} as 5<x<10

y=x+5 . Let's plug in values

x=6 y=11
x=7 y=12
x=8 y=13
x=9 y=14

Now as we have to find maximum value I chose x=9 and y=14

So x+y=9+14=23

Can someone let me know where I am making mistake here
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Tango3
I am getting it 23.

x = { 6,7,8,9} as 5<x<10

y=x+5 . Let's plug in values

x=6 y=11
x=7 y=12
x=8 y=13
x=9 y=14

Now as we have to find maximum value I chose x=9 and y=14

So x+y=9+14=23

Can someone let me know where I am making mistake here

Hi Tango3, the question here asks for the max integer value of x+y, but nowhere it mentions x and y are integers.

x+y = x+(x+5) = 2x + 5. So, to make the sum an integer, x should assume the value 9.5

So the max sum is 24.
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If x=9.99
y=14.99
x+y=24.98
x+y≈25

Answer D
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5 < x < 10 and y = x + 5

=> 5 < x < 10 ...(1)

Adding 5 on both the sides we get
=> 5 + 5 < x + 5 < 10 + 5
=> 10 < x + 5 < 15
=> 10 < y < 15 ...(2)

(1) + (2) we get

5 + 10 < x + y < 10 + 15
=> 15 < x + y < 25

So, Max(x+y) = 24 based on the options

=> Answer will be D
Hope it helps!

Watch the following video to learn the Basics of Inequalities

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