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A publishing company produced a record high of 180 books today. In the 9 days prior to today, the same publishing company had produced an average (arithmetic mean) of x books per day. If today’s record high increased average daily production to y books per day, what is x in terms of y?


A) \(\frac{9y+180}{10}\)

B) \(\frac{10y+180}{9}\)

C) \(\frac{9y-180}{9}\)

D) \(\frac{10y-180}{9}\)

E) \(\frac{10y}{9}-10\)

In the 9 days prior to today, the publishing company produced total of \(9x\) books.

Total books produced in 9+1=10 days is \(180+9x\).

Since we are told that the average daily production for these 10 days was \(y\), then \(y=\frac{180+9x}{10}\). Solving for \(x\) gives: \(x=\frac{10y-180}{9}\).

Answer: D.

Or: say \(x=0\), then in the 9 days prior to today, the publishing company produced total of \(9x=0\) books. So, we'll have that \(y=\frac{180+0}{10}=18\).

Now, plug \(y=18\) into the answer choices to see which one yields 0. Only answer choices D works: \(\frac{10*18-180}{9}=0\).

Answer: D.

Note that for plug-in method it might happen that for some particular number(s) more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.

Hope it helps.


Thanks.. I'm wondering what approach you have when picking smart numbers? How do you quickly choose a good one. For this question there are so many that yields a non-integer for the plug-in number. Are there cases where you can see that it is safe to use zero as a smart number compared to cases where using zero will not work?

Well, it really depends on the problem at hand.

Generally, if there are no constraints on the value of the variable, I try to use simplest numbers like 0 or 1. For this particular problem, since x=0 gives integer value of y, I went with it.

Alternately, you could use any multiple of 10 for x in order to get integer value of y.
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