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C
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Difficulty:
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Question Stats:
88% (01:22) correct
12%
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wrong
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In a certain school, the ratio of boys to girls is 5 to 13. If there are 72 more girls than boys, how many boys are there?
A. 27
B. 36
C. 45
D. 72
E. 117
A. 27
B. 36
C. 45
D. 72
E. 117
This is a pretty simple problem, however I was looking for purely algebraic way(s) to solve it. For some reason have trouble expressing it properly, please help to set it up.
24 Sep 2012, 04:19
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ikokurin
Given: \(\frac{b}{g}=\frac{5x}{13x}\), for some positive integer \(x\). So, the number of boys must be a multiple of 5. Only answer choice C fits.
Answer: C.
Alternately you can write: \(5x+72=13x\) --> \(x=9\) --> \(boys=5x=5*9=45\).
Answer: C.
Hope it helps.
General Discussion
24 Sep 2012, 12:18
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we know 5/13 and this is also equal to x/x+72. ---> 5x + 360 = 13x ---> x = 45.
Albeit, the Bunuel's approach is even more straight
Albeit, the Bunuel's approach is even more straight
