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Bunuel
When the even integer n is divided by 9, the remainder is 8. Which of the following, when added to n, gives a sum that is divisible by 18?

A. 1
B. 4
C. 9
D. 10
E. 17

Given that \(n=9q+8\) and n is even, n could be 8, 26, 44, ...

What number from answer choices when added to 8 (for example) yields a multiple of 18? It's 10!

Answer: D.

Is there a way to use answer choices?
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Start with the given equation:
\[ \frac{n}{9} = Q + \frac{9}{8} \]

**Step 1:** Understand the Formula
- If the formula above seems confusing, it's a commonly used "tactic" to answer remainder questions.
- If you need more clarity feel free to PM me for a detailed explanation on how I got that.

**Step 2:** Simplify the Equation
- Simplify the given equation to:
\[ n = 9Q + 8 \]

**Step 3:** Consider the Even Nature of the Number
- The problem states the number is even. This implies \(Q\) must be a multiple of not only \(9\) but also \(2\), ensuring the total remains even due to the constant term \(+8\).
- Thus, we adjust the equation to:
\[ n = (2)(9)Q + 8 \]
\[ n = 18Q + 8 \]

**Step 4:** Final Adjustment
- For \(n = 18Q +8\) to be divisible by \(18\) transform the \(+8\) into a \(+18\), by simply adding \(10\).

**Conclusion:**
- The manipulation reveals the necessity to add \(10\) to align with the condition. This leads us to our final answer, d.
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­Classic remainder problem. N= 9k + 8 and also its even so gotta add 10:

­
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