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13 Aug 2013, 00:05
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
77% (01:37) correct
23%
(01:59)
wrong
based on 429
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Fernando purchased a university meal plan that allows him to have a total of 3 lunches and 3 dinners per week. If the cafeteria is closed on weekends and Fernando always goes home for a dinner on Friday nights, how many options does he have to allocate his meals?
(A) 20
(B) 24
(C) 40
(D) 100
(E) 120
(A) 20
(B) 24
(C) 40
(D) 100
(E) 120
5C3 × 4C3
13 Aug 2013, 00:38
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Bookmarks
Hi,
Total number of days in a week=5(excluding weekends). Thus he has 5 lunch options and 5 dinner options to allocate his coupons to.
For lunch, he can divide his 3 lunch coupons in 5C3 ways.
Similarly, for 4 dinner options(excluding Friday), he can divide it in 4C3 ways.
Thus total ways=5C3*4C3
Regards
Argha
Total number of days in a week=5(excluding weekends). Thus he has 5 lunch options and 5 dinner options to allocate his coupons to.
For lunch, he can divide his 3 lunch coupons in 5C3 ways.
Similarly, for 4 dinner options(excluding Friday), he can divide it in 4C3 ways.
Thus total ways=5C3*4C3
Regards
Argha
13 Aug 2013, 02:08
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aishu4
He can allocate his 3 free lunches on any 3 days from 5 (excluding weekends), so in 5C3 ways.
He can allocate his 3 free dinners on any 3 days from 4 (excluding weekends and Friday), so in 4C3 ways.
Total = 5C3*4C3 ways.
Hope it's clear.
