The three digits of a number add up to 11. The number is div

Question

The three digits of a number add up to 11. The number is divisible by 5. The leftmost digit is double the middle digit. What is the product of the three digits?

A. 40
B. 72
C. 78
D. 88
E. 125

mau5 · Answer

As the number is divisible by 5, the product of the three digits must be divisible by 5. Only A and E subscribe to that.
Now, it is very easy to see that 40 = 5*8 = 5*4*2 and 5+4+2=11.
A.

fameatop · Answer

xyz is a three digit integer divisible by 5. So z can take only 0 or 5. We are also given that x = 2y
This means x+y (2y+y) must be a multiple of 3

xy5 or xy0
 CASE 1 
x+y+0 = 11
x+y=11
This can't be the case because 11 is not a multiple of 3

CASE 2 
x+y+5 = 11
x+y=6
solving we get, x=4 & y=2
So the 3 digit number is 425
Thus the product of the digits will be = 4 x 2 x 5 = 40
Answer A

Bunuel · Answer

Say the three-digit number is abc.

The leftmost digit is double the middle digit --> a=2b;
The number is divisible by 5 --> c is either 0 or 5;
The three digits of a number add up to 11 --> a+b+c=11

So, either a+b+c=2b+b+0=11 or a+b+c=2b+b+5=11. The first equation does not give an integer value of b, so it's not the case. From the second we get that b=2 --> a=4 and c=5 --> a*b*c=40.

Answer: A.

pacifist85 · Answer

Since the sum is 11, it is really easy to try some values.

The last one is 0 or 5.
The first one is twice the second one.

So,
First one: 2
Second one: 1
Third one: 8, doesn't work

First one: 3
Second one: 6
Third one: 2, doesn't work

First one: 4
Second one: 2
Thirdd one: 5, works

There is no way you can have 0 as the last digit, because you cannot have anything more than 4 as the first digit.

So, 4*2*5 = 40  ANS A

fireinbelly · Answer

We can also solve this by estimating the answer with the help of answer choices if we can't figure out the correct way which Bunuel and others already suggested....

It is a 3 digit no. say abc and divisible by 5 so C has to be either 0 or 5. 
Now a=2b so number can be written as 2b*b*0 or 2b*b*5. In either case the last digit of the number will be 0 because 0 multiplied by anything gives 0 and 5*2*anything will also give last digit 0. 
There is only one answer with last digit as 0 which is A.

EMPOWERgmatRichC · Answer

Hi All,

When a question has a limited number of possibilities, you can sometimes "brute-force" your way to the solution.

Here, we have a bunch of facts to work with: 
1) A 3-digit number 
2) Digits add up to 11 
3) Number is evenly divisible by 5 (so it ends in 0 or 5) 
4) The first digit is double the second digit.

Starting with the last fact, we only have a four options: 
21_ 
42_ 
63_ 
84_

If you plug 0 in for the last digit, you WON'T end up with a sum of 11, so the last digit MUST be a 5 and the only possible 3-digt number is...

425

Now, answer the question...

Final Answer:  A

GMAT assassins aren't born, they're made, 
Rich

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The three digits of a number add up to 11. The number is div

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The three digits of a number add up to 11. The number is div

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