Asifpirlo wrote:

The three digits of a number add up to 11. The number is divisible by 5. The leftmost digit is double the middle digit. What is the product of the three digits?

A. 40

B. 72

C. 78

D. 88

E. 125

xyz is a three digit integer divisible by 5. So z can take only 0 or 5. We are also given that x = 2y

This means x+y (2y+y) must be a multiple of 3

xy5 or xy0

CASE 1x+y+0 = 11

x+y=11

This can't be the case because 11 is not a multiple of 3

CASE 2x+y+5 = 11

x+y=6

solving we get, x=4 & y=2

So the 3 digit number is 425

Thus the product of the digits will be = 4 x 2 x 5 = 40

Answer A

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