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mikemcgarry
Attachment:
4x4 grid.JPG
In the above diagram, the 16 dots are in rows and columns, and are equally spaced in both the horizontal & vertical direction. How many triangles, of absolutely any shape, can be created from three dots in this diagram? Different orientations (reflections, rotations, etc.) and/or positions count as different triangles. (Notice that three points all on the same line cannot form a triangle; in other words, a triangle must have some area.)
(A) 516
(B) 528
(C) 1632
(D) 3316
(E) 3344


Many GMAT math problems, such as this one, cannot be solved by formulas alone. For a discussion of the uses & abuses of formulas on the GMAT Quant section, as well as the complete solution to this problem, see:
https://magoosh.com/gmat/2014/gmat-math- ... -formulas/

Mike :-)

Number of ways to connect any 3 distinct dots = 16C3 = (16*15*14)/(3*2*1) = 560
Number of ways to connect any 3 distinct dots into a horizontal line (non-triangles) = 4C3*4 = 16
Number of ways to connect any 3 distinct dots into a vertical line (non-triangles) = 4C3 *4 = 16
Number of ways to connect any 3 distinct dots into top-left to bottom-right lines (non-triangles) = 1+4C3+1 = 6
Number of ways to connect any 3 distinct dots into bottom-left to top-right lines (non-triangles) = 1+4C3+1 = 6

Number of ways to connect any 3 distinct dots in the figure into a triangle = 560 - 16 - 16 - 6 - 6 = 516

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Hello,
Please can someone explain how to calculate the number number of ways to connect any 3 distinct dots into top-left to bottom-right line and into bottom-left to top-right lines.

Why is not 4C3 *2 ?? Why you need to sum 1+ 4C3 +1 ?
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very nice! Thks a lot !
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Given that there are 16 dots equally spaced in an array, any unique combination of E does chosen can be a valid triangle with positive area UNLESS those 3 points chosen are COLINEAR

to find the number of valid triangles:


(total possible unique combinations of 3 dots chosen out of the 16 total)

-

(Unfavorable Outcomes in which the 3 dots chosen all lie on the same line)



(16 c 3) = 16! / (3! 13!) = 560 unique combinations can be made of 3 dots


Out of these 560 groupings, how many groupings involve 3 dots located on the same Line


Case 1: vertical rows

For any one vertical row, there are 4 dots. Any 3 unique dots chosen from those 4 dots will lie on a straight line and will NOT form a valid triangle. How many ways can we have unique groups of 3 dots chosen out of 4 in a row?

(4 c 3) = 4 ways

Since there are 4 rows: (4 rows) * (4 combinations per row that do not form a triangle) = 16 invalid


Case 2: Same logic as case 1.

There will be another 16 invalid groupings.


Case 3: 3 dots that lie on Diagonally Upwards Sloping Lines

There are 2 Diagonally upward slopping lines that sandwich the Center Diagonal.

Each of those lines has only 3 dots. Each will be an invalid case ———> 2 invalid

The upward sloping diagonal of the 4 by 4 array contains 4 dots. Any 3 dots chosen from these 4 dots that lie on a diagonal straight line will NOT form a triangle.

(4 c 3) = 4 invalid

6 invalid cases


Case 4: downward sloping diagonal lines

Symmetrically, the same logic will apply as applied in case 3.

Another 6 invalid cases that must be removed.


Total number of possible triangles = (560) - (16) - (16) - (6) - (6) =

(560) - (44) =


516 possible triangles can be made

Answer (A)

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