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earnit
A sum of $3310 is to be paid back in 3 equal installments. How much is each installment if the interest is compounded annually at 10% per annum.

A. 1311
B. 1331
C. 1103
D. 2331
E. 2311



The Thread containing the above question is locked. Hence, I am posting it here.

What is wrong in this approach?
3310**1.1 = 3641
now divide by 3 = ~1213

Similar question to practice: louie-takes-out-a-three-month-loan-of-1000-the-lender-101506.html

Check other Compound Interest Problems in our Special Questions Directory.

Hope it helps.
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why arent we supposed to apply ci formula here? when i substitute for the formula i got a different answer(total amount=3310*(1+0.1)^3=4405.6; interest to be paid= 1095.6).
Bunuel could u please help me here understand where i have gone wrong
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earnit
A sum of $3310 is to be paid back in 3 equal installments. How much is each installment if the interest is compounded annually at 10% per annum.

A. 1311
B. 1331
C. 1103
D. 2331
E. 2311



The Thread containing the above question is locked. Hence, I am posting it here.

What is wrong in this approach?
3310**1.1 = 3641
now divide by 3 = ~1213

The approach to solve this question is:

Assume each installment = X
Initial value = 3310

End of 1st year, value = 3310*1.1 AND we pay the first installment, so remaining value = 3310*1.1 - X = 3641 - X
End of 2nd year, value = (3641 - X)*1.1 AND we pay the second installment, so remaining value = (3641 - X)*1.1 - X = 4005 - 2.1X
End of 3rd year, value = (4005 - 2.1X)*1.1 = 4405 - 2.31X

KEY is the value at the end of 3rd year = X (the last installment)
=> 4405 - 2.31X = X
=> 4405 = 3.31X
=> X = 1331

Your approach is wrong because you used simple interest rate for only 1 year (3310*1.1). That's wrong. We have three years and compound interest rate.

Hope it helps.

While the above method is the correct one, in my opinion it is bit tedious to do the calculations by hand, at least for me.
To get an approximate value you can do the following:
Find the total amount with interest compounding over 2 years:
A=3310*(1+0.10)^2=4005.1
Now each installment is roughly A/3=4005.1/3=1335.03 which is close to the final answer 1331.

Since we are taking the interest on the whole 3310 even in the second year and we don't consider the little bit interest in the 3rd year, I find that the answer I get through this is always slightly more than the actual answer. But still, unless the answer choices are really close, you can save some time through this method.
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Teerex
pqhai
earnit
A sum of $3310 is to be paid back in 3 equal installments. How much is each installment if the interest is compounded annually at 10% per annum.

A. 1311
B. 1331
C. 1103
D. 2331
E. 2311



The Thread containing the above question is locked. Hence, I am posting it here.

What is wrong in this approach?
3310**1.1 = 3641
now divide by 3 = ~1213

The approach to solve this question is:

Assume each installment = X
Initial value = 3310

End of 1st year, value = 3310*1.1 AND we pay the first installment, so remaining value = 3310*1.1 - X = 3641 - X
End of 2nd year, value = (3641 - X)*1.1 AND we pay the second installment, so remaining value = (3641 - X)*1.1 - X = 4005 - 2.1X
End of 3rd year, value = (4005 - 2.1X)*1.1 = 4405 - 2.31X

KEY is the value at the end of 3rd year = X (the last installment)
=> 4405 - 2.31X = X
=> 4405 = 3.31X
=> X = 1331

Your approach is wrong because you used simple interest rate for only 1 year (3310*1.1). That's wrong. We have three years and compound interest rate.

Hope it helps.

While the above method is the correct one, in my opinion it is bit tedious to do the calculations by hand, at least for me.
To get an approximate value you can do the following:
Find the total amount with interest compounding over 2 years:
A=3310*(1+0.10)^2=4005.1
Now each installment is roughly A/3=4005.1/3=1335.03 which is close to the final answer 1331.

Since we are taking the interest on the whole 3310 even in the second year and we don't consider the little bit interest in the 3rd year, I find that the answer I get through this is always slightly more than the actual answer. But still, unless the answer choices are really close, you can save some time through this method.

Big agree here. This calculation will already take close to 2 minutes with the "shortcut" method
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Is it correct to assume that installments are yearly?
well i assumed as 3 monthly installments and landed
yearly interest=3310*0.1=331
3 months interest= 331*3/12=82.75
monthly installments=1130.81 not in the options
then followed the yearly installments method
please someone will suggest me a faster method to decide for the assumption?
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Looking at the numbers here, whoever created this question most likely intended the question to be solved by the PMT formula, which looks like this:

Payments per installment = Principal * [r*(1+r)^n] / [(1+r)^n -1]
Where r = interest rate and n = # of instalments

First calculate (1+r)^n which is 1.331. Notice that 1.331 is no coincidence with the principal of 3310

3310 * [0.1*1.331] / [1.331 - 1]
3310 * [0.1331] / [0.331]

Now by simplifying we get 1331. I don't think the GMAT requires to know the PMT formula though
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