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Bunuel

Tough and Tricky questions: Combinations.



How many ways could three people sit at a table with five seats in which two of the five seats will remain empty?

A) 8
B) 12
C) 60
D) 118
E) 120

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Source: Chili Hot GMAT

The correct answer is C.
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Bunuel

Tough and Tricky questions: Combinations.



How many ways could three people sit at a table with five seats in which two of the five seats will remain empty?

A) 8
B) 12
C) 60
D) 118
E) 120

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Source: Chili Hot GMAT

5 Chairs 3 people need to be seated.

__ __ __ __ __

1st person can sit in 5 ways. Hence

5 __ __ __ __ __

2nd person can sit in only 4 ways since the 1st person occupied seat.

5 4 __ __ __

3rd person can sit in 3 ways since three empty chairs are there.

5 4 3 __ __

So total number of three person can sit in 5 chair is = 5*4*3 = 20*3 = 60
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Quote:


How many ways could three people sit at a table with five seats in which two of the five seats will remain empty?

A) 8
B) 12
C) 60
D) 118
E) 120

The number of choices for a seat the first person could have is 5. Once he has sat down, the number of choices for a seat the second person could have is 4. Finally, the number of choices for a seat the third person, after the first two have sat down, could have is 3. Thus, the number of ways 3 people can sit a table of with five seats is:

5 x 4 x 3 = 60

Alternate Solution:

The number of seats to be occupied can be selected in 5C3 = 5!/(3!*2!) = (5x4)/2 = 10 ways.

Once the seats to be occupied are determined, there are 3! = 6 ways the three people can be arranged in those seats.

In total, there are 10 x 6 = 60 ways the three people can sit at a table of five seats.

Answer: C
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