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24 Feb 2015, 02:56
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
76% (00:59) correct
24%
(01:24)
wrong
based on 207
sessions
History
Date
Time
Result
Not Attempted Yet
How many different numbers can we have by changing the position of the digits of the number 718844?
a) 15
b) 90
c) 180
d) 360
e) 720
a) 15
b) 90
c) 180
d) 360
e) 720
24 Feb 2015, 04:35
Kudos
Bookmarks
Awli
THEORY
Permutations of \(n\) things of which \(P_1\) are alike of one kind, \(P_2\) are alike of second kind, \(P_3\) are alike of third kind ... \(P_r\) are alike of \(r_{th}\) kind such that: \(P_1+P_2+P_3+..+P_r=n\) is:
\(\frac{n!}{P_1!*P_2!*P_3!*...*P_r!}\)
For example number of permutation of the letters of the word "gmatclub" is \(8!\) as there are 8 DISTINCT letters in this word.
Number of permutation of the letters of the word "google" is \(\frac{6!}{2!2!}\), as there are 6 letters out of which "g" and "o" are represented twice.
According to the above, the number of arrangements of 6-digit number 718844, where 8's and 4's are repeated twice is 6!/(2!2!) = 180.
Answer: C.
Hope it's clear.
