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pacifist85
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I was wondering if it was necessary to go through this.

For example, we know that the probability of heads (or tails) is 1/2. To find how this probability changes according to the times we flip, we increase to the respective power. So, for 2 flips it would be (1/2)^2 = 1/4.

Now, to find the least number of flips that would produce a probability of less than 0.01%, couldn't we just plug in the higest number and see if it works?

So, we could do: (1/2)^14. We can relatively quickly find that 2^14= 16384. If we divide 1 by 16384 we end up with 0.000..., which is where we can stop the calculation, as it already is ower than 0.001.

Is this right?
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pacifist85
Randy is going to flip a coin x times. What is the minimum value of x for which the probability that he flips all heads is less than 0.01%?

A. 10
B. 11
C. 12
D. 13
E. 14


\(P(H) = 1/2\)
if she flips X times, the probability of all HEADS is \((1/2)^x\)
question is asking
\(if (1/2)^x < 1/10000\) , what is the minimum value of x ?
\(x=14\)
Option E
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Hi pacifist85,

The question asks us to find the MINIMUM number of flips that will yield the desired result. By definition, the largest answer MUST be less than .01%, but we won't immediately know if that answer is the minimum answer.

The work that you would do to prove that 2^14 is less than .01% is essentially a 'step-by-step' calculation, so you should be able to tell if 2^12 or 2^13 was small enough (once you got to those 'steps' in the calculation). Since you're 'counting doubles' anyway, there's really not much of difference between what you're talking about and what the official solution provides.

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pacifist85
Randy is going to flip a coin x times. What is the minimum value of x for which the probability that he flips all heads is less than 0.01%?

A. 10
B. 11
C. 12
D. 13
E. 14

less than 0.01 = 1/100 * 1/100 = 1/10,000
(1/2)^2 = 1/4
^3 = 1/8
^4 = 1/16
^5 = 1/32
^6 = 1/64
^7 = 1/128
^8 = 1/256
^9 = 1/512
^10 = 1/1024 - A is out
^11 = 1/2048 - B is out
^12 = 1/4096 - C is out
^13 = 1/8192 - D is out

the answer must be E.

alternatively, we should know that 2^10 = 1024. - and we can start from there...
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Here is a detailed solution.

Please don't hesitate if you have any question

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