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Lucky2783
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In case anyone wants to know the values of variables w, x, y, and z to double check their algebra, or is as OCD as I, below are their values:

w= -1
x= 3
y= 5
z= -2
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we have to find n ie - 3X+W.
So try to understand the different combinations that would result in this equation.

tip: write all the equations down and it can be easily found

TAKING THESE THREE EQUATIONS :

2W+X+Y=6----->1
2X+Y+Z=9------->2

adding 1 and 2 we get: 2W+3X+2Y+Z=15 ----->3
now,
W+2Y+Z=7----->4

subtract 4 from 3

to get w+3x=8

n=8
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Lucky2783
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W, X, Y and Z each represent a different number. If the sum of each column is shown beneath that column, and the sum of each row is shown beside that row, then n =

A) 6
B) 7
C) 8
D) 9
E) 10

We see that from the first row, we have 2X + W + Z = 3 and from the first column, X + W + 2Z = -2. If we subtract the 2nd equation from the first, we have X - Z = 5. Thus Z = X - 5. Plug this back to the first equation, we have:

2X + W + (X - 5) = 3

3X + W - 5 = 3

3X + W = 8

Notice that n as the sum of the 3rd column is 3X + W, so n must be 8.

Answer: C
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First row: 2X + W + Z = 3

First column: 2Z + W + X = -2

Third column: 3X + W = n


First row - first column: 2X + W + Z - 2Z - W - X =3 -( -2)

=> X - Z = 5 or Z = X - 5 [Putting back in 1st row]

=> 2X + W + (X - 5) = 3

=> 3X + W = 8

And Third column: 3X + W = n

Therefore n = 8

Answer C
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@bunnel can you post links to similar questions?
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sing086
@bunnel can you post links to similar questions?


Check here: ALPHAMETIC QUESTIONS ON THE GMAT
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W+2Z=-2
2y+Z=7
2x+W=n
W+X+Y=5

add all above Equation-
3W+3X+3Y+3Z=10+n

W+X+Y+Z=3+(n+1)/3

one by one put all given values from options to get the solution -

n=8 will solve above equation.

Ans- C
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