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C
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Difficulty:
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Question Stats:
80% (01:16) correct
20%
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wrong
based on 758
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What is the median of a set of consecutive integers if the sum of nth number from the beginning and nth number from the end is 100?
This question is a part of the series of original questions posted by PrepTap. Follow us to receive more questions like this.
- A. 10
B. 25
C. 50
D. 75
E. 100
This question is a part of the series of original questions posted by PrepTap. Follow us to receive more questions like this.
28 Apr 2015, 09:44
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Surprisingly no one answered this easy one.
property of a set of consecutive integerz.
mean=median=(first element+last element)/2 = (second element+last but one element)/2 =(third element+ third last element)/2 Etc. Etc.
So mean=median=100/2=50
property of a set of consecutive integerz.
mean=median=(first element+last element)/2 = (second element+last but one element)/2 =(third element+ third last element)/2 Etc. Etc.
So mean=median=100/2=50
General Discussion
07 Jun 2016, 01:21
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PrepTap
nth term from start: a+ (n-1) [ common difference is 1]; a is the first term.
nth term from end: l+(n-1) (-1) [here common difference would be -1]; l is the last term.
(a+n-1) + (l-n+1) = a+ l = 100.
In case of consecutive integers or an AP.
Mean = median = 0.5 * (First term+ Last term) = 0.5 * 100 = 50.
C is the answer.
