Hi Turkish,
This ratio-based question can be solved in a number of different ways; you can take an Algebraic approach or you can use a combination of TESTing VALUES and the TESTing THE ANSWERS.
We're given a few facts about the make-up of an organization from 2000 to 2001
1) The number of male members INCREASED by 12%
2) The number of female members DECREASED by 6%
3) The overall membership INCREASED by 1.2%
We're asked for the ratio of male members to female members in the year 2000.
To start, I'm going to prove something about the ratio in the year 2000....
IF....we had an equal number of male members and female members, the membership increase would have been GREATER than 1.2%.....Here's proof:
IF.....in 2000
Males = 100
Females = 100
Total = 200
in 2001
Males = 112
Females = 94
Total = 206
The total increase from year to year would be 6/200 = 3%
Since we're told that the total increase was 1.2%, that means that there had to be MORE women than men in 2000 (which would end in a % change that would be less than 3%) - probably not that many more women, but enough to bring down the percent. Eliminate answers D and E.
From the remaining 3 answers, we can TEST VALUES, using the ratios in the answers to select our VALUES. From the 3 options, we have....
Answer A: Females is DOUBLE the number of males
Answer B: Females is TRIPLE the number of males
Answer C: Females is 50% more than the number of males
Answer C involves the smallest difference, so I'm going to start there...
IF.....in 2000
Males = 200
Females = 300
Total = 500
in 2001
Males = 224
Females = 282
Total = 506
The total increase from year to year would be 6/500 = 1.2%
This is an exact MATCH for what we were told, so we have the correct answer.
Final Answer:
GMAT assassins aren't born, they're made,
Rich