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Hemavakade
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Given two sets A = {1,1,2,2,3,3} and B = {0,1}, if one number is chose Updated on: 23 Sep 2015, 17:21
Originally posted by Hemavakade on 23 Sep 2015, 17:08.
Last edited by ENGRTOMBA2018 on 23 Sep 2015, 17:21, edited 1 time in total.
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C
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72% (01:30) correct 28% (01:41) wrong based on 152 sessions

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Given two sets A = {1,1,2,2,3,3} and B = {0,1}, if one number is chosen from each set at random, what is the probability that the sum of both numbers is an even number

A) 1/6
B) 1/3
C) 1/2
D) 2/3
E) 1

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C
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BrentGMATPrepNow
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Given two sets A = {1,1,2,2,3,3} and B = {0,1}, if one number is chose 23 Sep 2015, 17:14
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Hemavakade
Given two sets A = {1,1,2,2,3,3} and B = {0,1}, if one number is chosen from each set at random, what is the probability that the sum of both numbers is an even number

A) 1/6
B) 1/3
C) 1/2
D) 2/3
E) 1
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One way to look at it:

The number from set A can be ANYTHING.
The number selected from set B will determine whether the sum is odd or even.

For example, if a 2 is selected from set A, we need a 0 from set B to get an even sum.
If a 3 is selected from set A, we need a 1 from set B to get an even sum.
And so on.

So, P(sum is even) = P(select ANY number from set A AND select the number from set B that makes the sum even)
= P(select ANY number from set A) x P(select the number from set B that makes the sum even)
= 1 x 1/2
= 1/2
= C
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Given two sets A = {1,1,2,2,3,3} and B = {0,1}, if one number is chose 23 Sep 2015, 17:17
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Hemavakade
Given two sets A = {1,1,2,2,3,3} and B = {0,1}, if one number is chosen from each set at random, what is the probability that the sum of both numbers is an even number

A) 1/6
B) 1/3
C) 1/2
D) 2/3
E) 1
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Or we can examine all of the possible outcomes in the form (# from set A, # from set B):
(1, 0)
(1, 0)
(1, 1)
(1, 1)
(2, 0)
(2, 0)
(2, 1)
(2, 1)
(3, 0)
(3, 0)
(3, 1)
(3, 1)

There are 12 equally-likely outcomes and 6 of them have an even sum.

So, P(sum is even) = 6/12 = 1/2
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Given two sets A = {1,1,2,2,3,3} and B = {0,1}, if one number is chose 24 Sep 2015, 07:09
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Hemavakade
Given two sets A = {1,1,2,2,3,3} and B = {0,1}, if one number is chosen from each set at random, what is the probability that the sum of both numbers is an even number

A) 1/6
B) 1/3
C) 1/2
D) 2/3
E) 1

Kudos, if you like the post :)
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Another approach:

P(sum is even) = P(both selected numbers are even OR both selected numbers are odd)
= P(even from set A AND even from set B OR odd from set A AND odd from set B)
= P(even from set A) x P(even from set B) + P(odd from set A) x P(odd from set B)
= 2/6 x 1/2 + 4/6 x 1/2
= 1/6 + 2/6
= 1/2
= C
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Given two sets A = {1,1,2,2,3,3} and B = {0,1}, if one number is chose 20 Feb 2026, 05:46
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