Let C be defined as the sum of all prime numbers between 0 and 30.

Question

Let C be defined as the sum of all prime numbers between 0 and 30. What is C/3

A. 155
B. 129
C. 61
D. 47
E. 43

Skywalker18 · Answer

Prime numbers between 0 and 30 - 2 , 3 , 5 , 7, 11 , 13 , 17 , 19 , 23 , 29
Sum,C = 129
C/3 = 43

Answer E

Konstantin1983 · Answer

Is there other way besides counting numbers?

stonecold · Answer

I dont think so .
Not really .

Regards
Stone Cold

OptimusPrepJanielle · Answer

C = 2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 + 29 = 129
C/3 = 129/3 = 43.

Option E

NDND · Answer

prime numbers: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29

Then I started to cancel numbers whose units numbers summing to 10:
 2, 5, 23  ... 3,7 ...,  11,19 ....  13, 17 ,.... , 29

only 9 remained in the unit number
9/3 = 3 ....only E ends with 3

Option E

ScottTargetTestPrep · Answer

The sum of the prime numbers from 0 to 10 is:

2 + 3 + 5 + 7 = 17

The sum of the prime numbers from 11 to 20 is:

11 + 13 + 17 + 19 = 60

The sum of the prime numbers from 21 to 30 is:

23 + 29 = 52

So C/3 = (17 + 60 + 52)/3 = 129/3 = 43.

Answer: E

MagnusSamIBA · Answer

Prime numbers between 0 and 30: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
Sum (C) = 2+3+5+7+11+13+17+19+23+29 = 129
C/3 = 129/3 = 43
Answer: E (43)

Prep Toolkit