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Let C be defined as the sum of all prime numbers between 0 and 30.

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Let C be defined as the sum of all prime numbers between 0 and 30.  [#permalink]

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New post 09 Nov 2015, 00:27
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

80% (01:34) correct 20% (01:32) wrong based on 124 sessions

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Re: Let C be defined as the sum of all prime numbers between 0 and 30.  [#permalink]

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New post 09 Nov 2015, 01:35
Prime numbers between 0 and 30 - 2 , 3 , 5 , 7, 11 , 13 , 17 , 19 , 23 , 29
Sum,C = 129
C/3 = 43

Answer E
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Re: Let C be defined as the sum of all prime numbers between 0 and 30.  [#permalink]

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New post 16 Apr 2016, 05:53
Is there other way besides counting numbers?
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Re: Let C be defined as the sum of all prime numbers between 0 and 30.  [#permalink]

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New post 21 Apr 2016, 11:48
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Re: Let C be defined as the sum of all prime numbers between 0 and 30.  [#permalink]

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New post 22 Apr 2016, 02:15
Bunuel wrote:
Let C be defined as the sum of all prime numbers between 0 and 30. What is C/3

A. 155
B. 129
C. 61
D. 47
E. 43


C = 2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 + 29 = 129
C/3 = 129/3 = 43.

Option E
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Re: Let C be defined as the sum of all prime numbers between 0 and 30.  [#permalink]

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New post 22 Apr 2016, 10:42
Bunuel wrote:
Let C be defined as the sum of all prime numbers between 0 and 30. What is C/3

A. 155
B. 129
C. 61
D. 47
E. 43


Prime numbers between 0 - 10 = 2 , 3 , 5 , 7 ( Sum = 17)

Prime numbers between 11 - 20 = 11 , 13 ,17 ( Sum = 41)

Prime numbers between 21 - 30 = 19, 23, 29 ( Sum = 71)

Sum of all the prime numbers will be 129 ( 71 + 41 + 17 )
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Re: Let C be defined as the sum of all prime numbers between 0 and 30.  [#permalink]

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New post 03 Apr 2018, 05:44
prime numbers: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29

Then I started to cancel numbers whose units numbers summing to 10:
2, 5, 23 ...3,7..., 11,19.... 13, 17,.... , 29

only 9 remained in the unit number
9/3 = 3 ....only E ends with 3

Option E
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Re: Let C be defined as the sum of all prime numbers between 0 and 30. &nbs [#permalink] 03 Apr 2018, 05:44
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