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Bunuel
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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GMAT 1: 800 Q51 V49
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Bunuel
Amanda goes to the toy store to buy 1 ball and 3 different board games. If the toy store is stocked with 3 types of balls and 6 types of board games, how many different selections of the 4 items can Amanda make?

A. 9
B. 12
C. 14
D. 15
E. 60

This is a simple question that tests your concepts about combinations.

We need to select 1 ball out of 3 available and 3 board games out of 6 available.
This can be done in 3C1*6C3 ways = 3*\(\frac{{6!}}{{3!*3!}}\) = 3*20 = 60

Option E
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Pretty Straight.

Choose 1 ball from 3 - 3C1 = 3/1 = 3
Choose 3 board games from 6 - 6C3 = (6*5*4)/(1*2*3)= 20

Total number of ways the selection can happen is = 3 * 20 = 60
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3C1*6C3=3*20 = 60

Correct answer - E
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I do not get logic. The explaination in the Kaplan book doesn't tell clearly why you multiply 3*20 and why you use the combination formula.
can someone explain why you multiply 3*20 and why you use combination insteat of permutation?
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Bunuel
Amanda goes to the toy store to buy 1 ball and 3 different board games. If the toy store is stocked with 3 types of balls and 6 types of board games, how many different selections of the 4 items can Amanda make?

A. 9
B. 12
C. 14
D. 15
E. 60

Amanda can select a ball in 3C1 = 3 ways and she can selected a board game in 6C3 = 6!/[3!(6-3)!] = (6 x 5 x 4)/3! = (6 x 5 x 4)/(3 x 2 x 1) = 20. So, the total number of ways is 3 x 20 = 60.

Answer: E
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