Last visit was: 24 Apr 2026, 12:36 It is currently 24 Apr 2026, 12:36
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,820
Own Kudos:
811,058
 [8]
Given Kudos: 105,873
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,820
Kudos: 811,058
 [8]
A club wants to mix 20 pounds of candy worth $8.00 per pound with cand 14 Feb 2016, 04:08
3
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

5% (low)

Question Stats:

90% (01:32) correct 10% (01:52) wrong based on 246 sessions

History

Date
Time
Result
Not Attempted Yet
A club wants to mix 20 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?

A. 20
B. 30
C. 40
D. 50
E. 60
ShowHide Answer
Official Answer
C
User avatar
Skywalker18
User avatar
Retired Moderator
Joined: 08 Dec 2013
Last visit: 15 Nov 2023
Posts: 1,973
Own Kudos:
10,169
 [1]
Given Kudos: 171
Status:Greatness begins beyond your comfort zone
Location: India
Concentration: General Management, Strategy
GPA: 3.2
WE:Information Technology (Consulting)
Products:
My Reviews
Posts: 1,973
Kudos: 10,169
 [1]
A club wants to mix 20 pounds of candy worth $8.00 per pound with cand 14 Feb 2016, 10:55
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let number of pounds of 5$ candy to be used be w
6 = (20*8 + 5*w)/(20 +w)
=>120 + 6w = 160 + 5w
=> w = 40

Answer C
avatar
arturportugal
avatar
Joined: 25 Jun 2015
Last visit: 03 Dec 2016
Posts: 7
Own Kudos:
4
Given Kudos: 269
Location: Portugal
GMAT 1: 370 Q37 V37
GPA: 2.92
GMAT 1: 370 Q37 V37
Posts: 7
Kudos: 4
A club wants to mix 20 pounds of candy worth $8.00 per pound with cand 19 Jul 2016, 07:52
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A club wants to mix 20 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?

A. 20
B. 30
C. 40
D. 50
E. 60
Show more

Hi Bunuel,

Could you answer this exercise please? Thank you very much.
User avatar
BrentGMATPrepNow
User avatar
Major Poster
Joined: 12 Sep 2015
Last visit: 31 Oct 2025
Posts: 6,733
Own Kudos:
36,457
 [2]
Given Kudos: 799
Location: Canada
Expert
Expert reply
Posts: 6,733
Kudos: 36,457
 [2]
A club wants to mix 20 pounds of candy worth $8.00 per pound with cand 19 Jul 2016, 11:00
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A club wants to mix 20 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?

A. 20
B. 30
C. 40
D. 50
E. 60
Show more

One option is to use the weighted average formula:
Weighted average of groups combined = (group A proportion)(group A average) + (group B proportion)(group B average) + (group C proportion)(group C average) + ...

Let C = the number of pounds of CHEAP ($5/lb) candy needed
This means the TOTAL weight of candy = 20 + C

So, the PROPORTION of expensive candy = 20/(20+C)
And the PROPORTION of cheap candy = C/(20+C)

Now apply the formula:
6 = [20/(20+C)](8) + [C/(20+C)](5)
Simplify: 6 = 160/(20+C) + 5C/(20+C)
Multiply both sides by (20+C) to get: 6(20+C) = 160 + 5C
Simplify: 120 + 6C = 160 + 5C
Solve to get: C = 40

Answer:
Show Spoiler
C

RELATED VIDEO:
User avatar
CounterSniper
User avatar
Joined: 20 Feb 2015
Last visit: 14 Apr 2023
Posts: 611
Own Kudos:
859
Given Kudos: 74
Concentration: Strategy, General Management
Posts: 611
Kudos: 859
A club wants to mix 20 pounds of candy worth $8.00 per pound with cand 20 Jul 2016, 03:51
Kudos
Add Kudos
Bookmarks
Bookmark this Post
(20*8+5*x)=6(20+x)
160+5x=120+6x
x=40
avatar
ks11
avatar
Joined: 25 Sep 2016
Last visit: 22 Mar 2018
Posts: 4
Own Kudos:
8
 [1]
Given Kudos: 8
Schools: LBS MiM"18 MBS '18
WE:Analyst (Consulting)
Schools: LBS MiM"18 MBS '18
Posts: 4
Kudos: 8
 [1]
A club wants to mix 20 pounds of candy worth $8.00 per pound with cand 06 Oct 2016, 05:02
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
A club wants to mix 20 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?

A. 20
B. 30
C. 40
D. 50
E. 60
--------------------------------------------------------------------------------------------
Cost of Candy A = $8.00 per pound
Cost of Candy B = $5.00 per pound
Cost of Candy A and Candy B Mixture = $6.00 per pound

Using Alligation Method

Candy A----------------Candy B

$8.00------------------$5.00
-----------$6.00------------
$1.00------------------$2.00

Ratio of Candy A to Candy B is 1:2

In order to find the weight of Candy B in the mixture, notice that the weight of Candy A in the mixture is already given, i.e., 20 pounds and as we know the ratio of Candy B is two times the ratio of Candy A in the mixture,

therefore the weight of Candy B in the mixture is 40 pounds.

Answer is 'C'

--------------------------------------------------------------------------------------------
+1 Kudos if you find this post helpful. Thanks!
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 24 Apr 2026
Posts: 22,286
Own Kudos:
26,534
 [1]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,286
Kudos: 26,534
 [1]
A club wants to mix 20 pounds of candy worth $8.00 per pound with cand 27 Aug 2019, 18:32
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
A club wants to mix 20 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?

A. 20
B. 30
C. 40
D. 50
E. 60
Show more


We can create the equation:

[8(20) + 5x]/(20 + x) = 6

160 + 5x = 120 + 6x

40 = x

Answer: C
User avatar
ThatDudeKnows
User avatar
Joined: 11 May 2022
Last visit: 27 Jun 2024
Posts: 1,070
Own Kudos:
1,030
Given Kudos: 79
Expert
Expert reply
Posts: 1,070
Kudos: 1,030
A club wants to mix 20 pounds of candy worth $8.00 per pound with cand 03 Jun 2022, 13:00
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A club wants to mix 20 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?

A. 20
B. 30
C. 40
D. 50
E. 60
Show more


If I see a chance to use PITA (Plugging In The Answers), I'm going for it! I like trying B and D.
Let's try B. 20 pounds of $8 candy is $160. 30 pounds of $5 candy is $150. That's a total of $310 and 50 pounds. That's more than $6/pound. Eliminate.
Let's try D. 20 pounds of $8 candy is $160. 50 pounds of $5 candy is $250. That's a total of $410 and 70 pounds. That's less than $6/pound. Eliminate.
We need something between the two.

Answer choice C.


ThatDudeKnowsPITA
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,976
Own Kudos:
1,117
Posts: 38,976
Kudos: 1,117
A club wants to mix 20 pounds of candy worth $8.00 per pound with cand 31 Oct 2024, 11:52
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Bunuel
Math Expert
109820 posts
Krunaal
Tuck School Moderator
853 posts