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Total wages = 15*90 -- (1)
Total wages excluding the 8th day= 7(87+92) = 7*179-- (2)
The difference between 1 and 2 should end in 7.
Hence D.
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Bunuel
The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $92 per day. What was his wage on the 8th day?

A. $83
B. $90
C. $92
D. $97
E. $104
First 7 days the worker gets $3 less than average and the last 7 days the worker gets $2 more than the average.
Hence during these 14 days the net change is negative $7.
Therefore, on the 8th he has to get $97.
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Bunuel
The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $92 per day. What was his wage on the 8th day?

A. $83
B. $90
C. $92
D. $97
E. $104

short cut only applicable for similar problem to save calculation time (in case we have tedious calc) => since total wage will be product of \(90 * 15\) it will always end with 0, and 8th day wage =\(TOTAL - 1st 7day - last 7 days\) or \(Total - (1st 7days + last 7 days)\)we can only do summation of products of Unit digits of 7 days and subtract the unit digit from 10, any option with that number is candidate answers.

1st 7 days = 7*7 = unit digit 9
last 7 days = 2*7 = unit digit 4

Unit digit of summation of these two = 3

So possible answer must end with 7 as unit digit, only possible answer is D


Large method
total 15 day of wages =>\(15*90 = 1350\)
1st 7 days wages =>\(7*87 = 609\)
last 7 days of wages =>\(7*92 = 644\)

8th day wage => \(1350 - 609 - 644 = 97\)
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Hi All,

We're told that the average pay a worker received for 15 consecutives working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $92 per day. We're asked for his wage on the 8th day.

There are a number of different ways to approach the 'math' in this question. Here's an approach that allows you to avoid a lot of 'step-heavy' math and focus on the 'relationships' between the numbers.

Since the average pay was $90/day, we can track how much 'below average' or 'above average' the individual days are...
-For the first 7 days, the average pay was $87/day, thus each of those days was $3 BELOW the average... meaning that we're (7)($3) = $21 'below' in total here.
-For the last 7 days, the average pay was $92/day, thus each of those days was $2 ABOVE the average... meaning that we're (7)($2) = $14 'above' in total here.

With those 14 days, we're a total of '$7 below' what the average is supposed to be, so that final day (the 8th day) has to make up for that difference...

8th day = $90 + $7 = $97

Final Answer:

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Bunuel
The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $92 per day. What was his wage on the 8th day?

A. $83
B. $90
C. $92
D. $97
E. $104

His wage on the 8th day was:

15 x 90 - 7 x 87 - 7 x 92 = 1350 - 609 - 644 = 97

Answer: D
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