A certain truck uses 18 gallons of diesel fuel in traveling 270 miles

Question

A certain truck uses 18 gallons of diesel fuel in traveling 270 miles. In order for the truck to travel the same distance using 10 gallons of diesel fuel, by how many miles per gallon must the truck’s fuel mileage be increased?

A. 8
B. 9
C. 12
D. 15
E. 27

A. 8
B. 9
C. 12
D. 15
E. 27

msk0657 · Answer

There are two sets 18G1 gallons and 10G2 gallons details given.

18 gallons covering 270 miles

Then 1 G1 is used to cover 15 miles.

Now for 10 G2 covering 270 miles.

then 1 G2 is used to cover 27 miles.

There must 27 - 15 = 12 miles per gallon increment is needed for 10 gallons to improve the mileage to cover 270 miles.

IMO C is correct answer.

OA please...will correct if I missed anything..

Divyadisha · Answer

Current mileage= 270/18 miles/gallon= 15 miles/gallon

New mileage= 270/10= 27 miles/gallon

by how many miles per gallon must the truck’s fuel mileage be increased= 27-15= 12 miles/gallon

DAllison2016 · Answer

ext{mpg} = \frac{	ext{distance (miles)}}{	ext{volume (gallons)}}

\frac{270}{18} = 15	ext{mpg}\
\frac{270}{10} = 27	ext{mpg} 
 27 - 15 = 12

C. 12

rhine29388 · Answer

Mileage =  \frac{distance}{gallons of fuel used}

original mileage of truck =  \frac{270}{18}  = 15 miles/gallon

new mileage of truck =  \frac{270}{10}  = 27 miles/gallon

so the mileage must be increased by 27 - 15 = 12 miles/gallon
Correct Answer - C

Subhrajyoti · Answer

In 18 gallons= 270 miles, therefore 1 gallon= 270/18 miles, thus in 10 gallons = (270*10)/18= 150 miles. Diffrential is 270-150= 120. Thus to cover 120 miles in 10 gallons you need 120/10= 12 miles extra mileage to be kicked in for us to cover 270 miles

Abhishek009 · Answer

\frac{270}{10} - \frac{270}{18}

= 27 - 15

= 12, Answer must be (C)

ScottTargetTestPrep · Answer

The current rate is 270/18 = 15 miles per gallon.

The new rate would need to be 270/10 = 27 miles per gallon.

So the truck’s fuel mileage must be increased by 27 - 15 = 12 mpg.

Answer: C

CrackverbalGMAT · Answer

CONCEPT: Percentage - Percentage increase/decrease. - For inversely proportional quantities, if there an increase in one of the quantities by a fraction of x/y(x/y*100 as a percentage), then the corresponding decrease in the other quantity is x/(x+y) -If there is a decrease in one of the quantities by a fraction of x/y, then the corresponding increase in the other quantity is x/|(y-x)|. SOUTION: Current mileage of the truck = Distance/Vol. of fuel used to cover that distance =270/18 = 15 miles/gallon Decrease in volume of fuel as a fraction = 18-10/18 = 4/9. Corresponding increase in mileage of the vehicle = 4/(9-4) = 4/5 Thus, mileage needs to increase by 4/5 of 15 =4/5*15 =12 miles/gallon.(C) Hope this helps

Keep studying

Devmitra Sen

Abhishek009 · Answer

Original Mileage is  \frac{270}{18} = 15 
Increased Mileage is  \frac{270}{10} = 27

So, Mileage must be increased by 12 miles/gallon, Answer must be (C)

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A certain truck uses 18 gallons of diesel fuel in traveling 270 miles

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A certain truck uses 18 gallons of diesel fuel in traveling 270 miles

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