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stonecold
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GRE 1: Q169 V154
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abhimahna
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Here is what id did in this Question ->
Let the 4 consecutive evens be ->
2n
2n+2
2n+4
2n+6

Taking their product => 2n*(2n+2)*(2n+4)*(2n+6)=> 2^4 n(n+1)(n+2)(n+3)

Property in action -> Product of n consecutive integers is always divisible by n!

Hence => 2^4 n(n+1)(n+2)(n+3)=2^4*24k
For some integer k.
Clearly Options 1,2,3,4 must be factors of 2^4*24k
But 80 has a 5 in it so it may or may nor be the factor of 2^4*24k
Hence we ned to exclude E from the answer choice.

Hence D.
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stonecold
Which of these must the factor of the product of four consecutive even integers:-
1) 48
2) 64
3) 96
4) 192
5) 80

A) 1,2 only
B) 2,3 only
C) 1,2,3 only
D) 1,2,3,4 only
E) All of them

say 2*4*6*8
this gives us
6*8=48
2*4*8=64
2*6*8=96
4*6*8=192
but not 5, so not 80
1,2,3,4 only
D
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abc568
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I think the question might be wrong here. Because, it dosnt mention, 'positive consecutive even numbers;
so, the lowest possible value can be 0,2,4,6; the product of which adds upto 48, & since the question is a 'must be', that means only 48 suffices as the correct answer.

Please let me know if I am missing something, because I am unsure.
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