Last visit was: 24 Apr 2026, 04:15 It is currently 24 Apr 2026, 04:15
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
NandishSS
Joined: 06 Jan 2015
Last visit: 28 Jan 2021
Posts: 701
Own Kudos:
1,787
 [40]
Given Kudos: 579
Location: India
Concentration: Operations, Finance
GPA: 3.35
WE:Information Technology (Computer Software)
Posts: 701
Kudos: 1,787
 [40]
1
Kudos
Add Kudos
39
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
abhimahna
User avatar
Board of Directors
Joined: 18 Jul 2015
Last visit: 06 Jul 2024
Posts: 3,481
Own Kudos:
5,779
 [5]
Given Kudos: 346
Status:Emory Goizueta Alum
Products:
Expert
Expert reply
Posts: 3,481
Kudos: 5,779
 [5]
2
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
General Discussion
User avatar
stonecold
Joined: 12 Aug 2015
Last visit: 09 Apr 2024
Posts: 2,231
Own Kudos:
3,643
 [2]
Given Kudos: 893
GRE 1: Q169 V154
GRE 1: Q169 V154
Posts: 2,231
Kudos: 3,643
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
RMD007
Joined: 03 Jul 2016
Last visit: 08 Jun 2019
Posts: 238
Own Kudos:
208
 [3]
Given Kudos: 80
Status:Countdown Begins...
Location: India
Concentration: Technology, Strategy
Schools: IIMB
GMAT 1: 580 Q48 V22
GPA: 3.7
WE:Information Technology (Consulting)
Products:
Schools: IIMB
GMAT 1: 580 Q48 V22
Posts: 238
Kudos: 208
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
Total Number of even numbers in 10-100 inclusive = 46 = 50(total in 100) - 4 (2,4,6,8).

Total numbers divisible by 3 in range 10-100 =\(\frac{99 - 12}{3}+ 1\) = \(\frac{87}{3} +1\) = 30 of which half will be even numbers. = 15.

Total even numbers not divisible by 3 are = 46 - 15 = 31.
avatar
Aldorado
Joined: 05 Feb 2014
Last visit: 06 Jun 2025
Posts: 20
Own Kudos:
12
 [1]
Given Kudos: 74
GMAT 1: 700 Q45 V40
GMAT 1: 700 Q45 V40
Posts: 20
Kudos: 12
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
First, let's consider the number of even numbers between 10 and 100, (extremes included)

(100-10)/2 + 1 = 46 even numbers

Now of these 46 even numbers, there are numbers which are also multiples of 3. The question asks us to find how many of these 46 numbers are not multiples of 3.

Remember, for an even number to be multiple of 3 , it has to be a multiple of 6 as well.

so, we've to weed out the multiples of 6 out of the above 46 numbers,

(96-12)/6 + 1 = 15 multiples of 6.

so the remaining numbers = 46 - 15 = 31 (C)
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 23 Apr 2026
Posts: 22,283
Own Kudos:
26,533
 [3]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,283
Kudos: 26,533
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
NandishSS
How many even number in the range between 10 to 100 inclusive are not divisible by 3

A) 15
B) 30
C) 31
D) 33
E) 46

We can first determine the number of even numbers from 10 to 100 inclusive:

(100 - 10)/2 + 1 = 90/2 + 1 = 46

We know that if a number is even and it is also divisible by 3, then it’s divisible by 6. Therefore, we need to determine the number of multiples from 10 to 100 inclusive and exclude these multiples from the 46 even numbers we’ve determined.

The number of multiples of 6 from 10 to 100 inclusive is:

(96 - 12)/3 + 1 = 84/6 + 1 = 14 + 1 = 15

Since there are 46 even numbers and 15 multiples of 6 (which are divisible by 3) from 10 to 100 inclusive, there must be 46 - 15 = 31 even numbers that are not divisible by 3.

Answer: C
User avatar
Seryozha
Joined: 04 Aug 2017
Last visit: 29 Nov 2019
Posts: 36
Own Kudos:
Given Kudos: 108
Status:No Progress without Struggle
Location: Armenia
GPA: 3.4
Posts: 36
Kudos: 20
Kudos
Add Kudos
Bookmarks
Bookmark this Post
RMD007
Total Number of even numbers in 10-100 inclusive = 46 = 50(total in 100) - 4 (2,4,6,8).

Total numbers divisible by 3 in range 10-100 =\(\frac{99 - 12}{3}+ 1\) = \(\frac{87}{3} +1\) = 30 of which half will be even numbers. = 15.

Total even numbers not divisible by 3 are = 46 - 15 = 31.


But why you did not include the 0 as an even number, the game changes, when we include 0 in the number list. Please explain.
User avatar
DelademAnku
Joined: 29 Mar 2023
Last visit: 08 Dec 2023
Posts: 8
Given Kudos: 18
Posts: 8
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Aldorado
First, let's consider the number of even numbers between 10 and 100, (extremes included)

(100-10)/2 + 1 = 46 even numbers

Now of these 46 even numbers, there are numbers which are also multiples of 3. The question asks us to find how many of these 46 numbers are not multiples of 3.

Remember, for an even number to be multiple of 3 , it has to be a multiple of 6 as well.

so, we've to weed out the multiples of 6 out of the above 46 numbers,

(96-12)/6 + 1 = 15 multiples of 6.

so the remaining numbers = 46 - 15 = 31 (C)








why 96-12? Can you explain a little further
User avatar
WiziusCareers1
Joined: 27 Apr 2009
Last visit: 24 Apr 2026
Posts: 178
Own Kudos:
Given Kudos: 35
Status:Not Applying
Location: India
Schools: HBS '14 (A)
GMAT 1: 730 Q51 V36
Schools: HBS '14 (A)
GMAT 1: 730 Q51 V36
Posts: 178
Kudos: 542
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The problem asks for the number of even integers in the range from 10 to 100 (inclusive) that are not divisible by 3.

We can solve this using the principle of inclusion-exclusion (or simply subtraction) by following these steps:

Step 1: Find the total number of even numbers in the range [10,100].

The even numbers are 10,12,14,...,100. This is an arithmetic progression. The number of terms can be found with the formula:

Count = {(Last Number−First Number)/Step} + 1
Total Even Numbers = {(100 - 10)/2} + 1 = 46
There are 46 even numbers in the range.

Step 2: Find the number of even numbers that are divisible by 3 in the range [10,100].

A number that is both even (divisible by 2) and divisible by 3 must be divisible by the least common multiple of 2 and 3, which is 6. We need to find the number of multiples of 6 in the range [10,100].

Let 6k be a multiple of 6. We are looking for integers k such that:
10 ≤ 6k ≤ 100
1.66 ≤ k ≤ 16.66
Since k must be an integer, the possible values for k are {2,3,4,...,16}.

The number of such multiples is:
Count=16−2+1=15
There are 15 even numbers (multiples of 6) that are divisible by 3 in the range.

Step 3: Find the number of even numbers that are not divisible by 3.
Subtract the number of even numbers that are divisible by 3 (from Step 2) from the total number of even numbers (from Step 1).
Even Numbers Not Divisible by 3 = Total Even Numbers − Even Numbers Divisible by 3
Even Numbers Not Divisible by 3 = 46 − 15 = 31
The final count is 31, which is option C.
Moderators:
Math Expert
109809 posts
Tuck School Moderator
853 posts