Last visit was: 24 Apr 2026, 13:51 It is currently 24 Apr 2026, 13:51
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
anairamitch1804
Joined: 26 Oct 2016
Last visit: 20 Apr 2019
Posts: 502
Own Kudos:
3,605
 [54]
Given Kudos: 877
Location: United States
Concentration: Marketing, International Business
Schools: HBS '19
GMAT 1: 770 Q51 V44
GPA: 4
WE:Education (Education)
Schools: HBS '19
GMAT 1: 770 Q51 V44
Posts: 502
Kudos: 3,605
 [54]
4
Kudos
Add Kudos
50
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
anairamitch1804
Joined: 26 Oct 2016
Last visit: 20 Apr 2019
Posts: 502
Own Kudos:
3,605
 [13]
Given Kudos: 877
Location: United States
Concentration: Marketing, International Business
Schools: HBS '19
GMAT 1: 770 Q51 V44
GPA: 4
WE:Education (Education)
Schools: HBS '19
GMAT 1: 770 Q51 V44
Posts: 502
Kudos: 3,605
 [13]
8
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
User avatar
gracie
Joined: 07 Dec 2014
Last visit: 11 Oct 2020
Posts: 1,028
Own Kudos:
2,022
 [5]
Given Kudos: 27
Posts: 1,028
Kudos: 2,022
 [5]
3
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
General Discussion
User avatar
JeffTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 04 Mar 2011
Last visit: 05 Jan 2024
Posts: 2,974
Own Kudos:
8,711
 [4]
Given Kudos: 1,646
Status:Head GMAT Instructor
Affiliations: Target Test Prep
Expert
Expert reply
Posts: 2,974
Kudos: 8,711
 [4]
1
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
anairamitch1804
The sum of the interior angle measures for any n-sided polygon equals 180(n – 2). If Polygon A has interior angle measures that correspond to a set of consecutive integers, and if the median angle measure for Polygon A is 140°, what is the smallest angle measure in the polygon?

(A) 130°
(B) 135°
(C) 136°
(D) 138°
(E) 140°

We need to first determine the number of sides (or angles) of polygon A. Let n denote the number of sides of polygon n. Since the interior angle measures correspond to consecutive integers, the median angle measure is also the average angle measure. Since sum = average x quantity, we have sum = 140n. Since we are also given that the sum of the interior angle measures equals 180(n - 2), it must be true that 140n = 180(n - 2). Thus:

140n = 180(n - 2)

140n = 180n - 360

-40n = -360

n = 9

We now know polygon A is a 9-sided polygon and there must be 4 angles that have measures less than the median angle measure (and 4 angles that have measures greater than the median angle measure). Since the median angle measure is 140 degrees and the angle measures are consecutive integers, the smallest angle measure must be 140 - 4 = 136 degrees.

Answer: C
avatar
rishit924
Joined: 12 Apr 2020
Last visit: 14 Apr 2021
Posts: 22
Own Kudos:
Given Kudos: 84
Posts: 22
Kudos: 5
Kudos
Add Kudos
Bookmarks
Bookmark this Post
anairamitch1804
Posting OE of this problem.

Dear Mam,

I was in an impression that 180(n-2)/n equation is applicable for regular polygons only.
Sum of angles we can find for any but divide by n is only possible for regular polygons.

Please advise.
Thanks in advance.
User avatar
IanStewart
User avatar
GMAT Tutor
Joined: 24 Jun 2008
Last visit: 24 Apr 2026
Posts: 4,143
Own Kudos:
11,278
 [2]
Given Kudos: 99
Expert
Expert reply
Posts: 4,143
Kudos: 11,278
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
rishit924

I was in an impression that 180(n-2)/n equation is applicable for regular polygons only.
Sum of angles we can find for any but divide by n is only possible for regular polygons.

180(n-2) is the sum of the n angles of any n-sided polygon. When we divide that by n, the total number of angles, we are finding the average size of an angle in an n-sided polygon. If the polygon is regular, every angle is the same, so in that case, every angle is equal to the "average" angle.

In a non-regular polygon, you can still calculate the average angle in your shape in this way. The average of the four angles in any quadrilateral, for example, will always be 90 degrees, even if no angle equals 90 degrees. In this question, because the angles are consecutive integers, the average and the median are equal (that's always true in any equally spaced set). So in this question, the average angle equals the median angle, so 180(n-2)/n = 140, and from there you can find n and answer the question.
User avatar
Archit3110
User avatar
Major Poster
Joined: 18 Aug 2017
Last visit: 24 Apr 2026
Posts: 8,629
Own Kudos:
Given Kudos: 243
Status:You learn more from failure than from success.
Location: India
Concentration: Sustainability, Marketing
GMAT Focus 1: 545 Q79 V79 DI73
GMAT Focus 2: 645 Q83 V82 DI81
GPA: 4
WE:Marketing (Energy)
Products:
GMAT Focus 2: 645 Q83 V82 DI81
Posts: 8,629
Kudos: 5,190
Kudos
Add Kudos
Bookmarks
Bookmark this Post
anairamitch1804
The sum of the interior angle measures for any n-sided polygon equals 180(n – 2). If Polygon A has interior angle measures that correspond to a set of consecutive integers, and if the median angle measure for Polygon A is 140°, what is the smallest angle measure in the polygon?

(A) 130°
(B) 135°
(C) 136°
(D) 138°
(E) 140°

the median of the angle sum can be written as
140 = 180(n-2)/ n
solve for n = 9
all consecutive angles
136,137,138,139..... 144
smallest is 136
option C
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,974
Own Kudos:
Posts: 38,974
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109818 posts
Tuck School Moderator
853 posts