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EgmatQuantExpert
The length, breadth, and height of a rectangular box are in the ratio of 6: 5: 4. If the length is halved, the breadth is doubled and the height is decreased by 100%, what would be percentage change in the volume of the box?


A. 25% increase
B. 25% decrease
C. 50% increase
D. 50% decrease
E. No change in volume.


Thanks,
Saquib
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Using same ratio l:b:h::6:5:4

Original volume = 120

New ratio l:b:h::3:10:0

New volume = 0

Hence,
Change in volume = 120-0/120 *100 = 100%

Where am i going wrong?

Thank you

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IMO D
Even i failed to understand what does 100% decrease in value mean but i then took a different way to solve the problem.
We are given that the length of a box becomes half that means it is now 50% of its previous value , its breadth is doubled that means 100% increase , then we are given that its height is decreased by 100 %.
So we have volume as a product of length , height and breadth.
Any change in the value of these quantities will reflect in the volume .So we have 50% decrease*100% increase*100% decrease which means that we need 50% more of length to get to our original value.
Hence D is answer.
Please correct me if i am wrong.
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EgmatQuantExpert
The length, breadth, and height of a rectangular box are in the ratio of 6: 5: 4. If the length is halved, the breadth is doubled and the height is decreased by 100%, what would be percentage change in the volume of the box?


A. 25% increase
B. 25% decrease
C. 50% increase
D. 50% decrease
E. No change in volume

Original Volume is 6*5*4 = 120

Increased Volume is 3*10*2 = 60

Thus, decrease in volume is 60

Percentage change in the volume of the box = 60/120*100 => 50%

Hence, answer must be (D) 50% decrease in volume...
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EgmatQuantExpert
The length, breadth, and height of a rectangular box are in the ratio of 6: 5: 4. If the length is halved, the breadth is doubled andthe height is decreased by 100%, what would be percentage change in the volume of the box?


A. 25% increase
B. 25% decrease
C. 50% increase
D. 50% decrease
E. No change in volume.


Thanks,
Saquib
Quant Expert
e-GMAT


Hi Saquib

Can you please elaborate this statement => "100 percent decrease in height"

How is that ever possible?

If you reduce the height by 100% then the Rectangular Box would cease to Exist.
If that is true.
New volume => Zero

And we none of the options would suffice.
If something gets reduced by 100 percent =>its new value would be Zero.


I hope i am not missing anything.

Regards
Stone Cold


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stonecold
EgmatQuantExpert
The length, breadth, and height of a rectangular box are in the ratio of 6: 5: 4. If the length is halved, the breadth is doubled andthe height is decreased by 100%, what would be percentage change in the volume of the box?


A. 25% increase
B. 25% decrease
C. 50% increase
D. 50% decrease
E. No change in volume.


Thanks,
Saquib
Quant Expert
e-GMAT


Hi Saquib

Can you please elaborate this statement => "100 percent decrease in height"

How is that ever possible?

If you reduce the height by 100% then the Rectangular Box would cease to Exist.
If that is true.
New volume => Zero

And we none of the options would suffice.
If something gets reduced by 100 percent =>its new value would be Zero.


I hope i am not missing anything.

Regards
Stone Cold




Hey Stone Cold,



Apologies for the inconvenience, I somehow missed the updates for this post. The decrease would be 50% and not 100%. I have updated the question.


Regards,
Saquib
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Hey Everyone,

Sorry for the mistake. I somehow confused everyone with the "100% decrease" information.

Otherwise the question is very straightforward.

    • Let the length, breadth and height be 6a, 5a and 4a.

    • Therefore, the initial volume of the box \(= 6a * 5a * 4a = 120a^3\).
    • New length \(= 6a * \frac{1}{2} = 3a\)
    • New breadth \(= 5a* 2 = 10a\)
    • New height \(= 4a * \frac{1}{2} = 2a\)
      o Therefore, the New Volume \(= 3a * 10a * 2a = 60a^3\).

    • Thus, Percentage change in volume \(= \frac{(120 – 60)*100}{120} = \frac{1}{2}*100 = 50\)% decrease.

Thus, the correct answer is Option D.


Thanks,
Saquib
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Even with incorrect value initially, many got the correct answer
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