Bunuel
If the product of two integers is an even number and the sum of the same two integers is an odd number, which of the following must be true?
A. The two integers are both odd.
B. The two integers are both even.
C. One of the two integers is odd and the other is even.
D. One of the integers is 1.
E. The two integers are consecutive.
Options for two integers whose product is even:
E / E (2 * 2 = 4)
O / E (3 * 2 = 6)
E / O (4 * 5 = 20)
Options for two integers whose sum is odd:
E / O (2 + 1 = 3)
O / E (7 + 4 = 11)
The second case limits the first. For sum to be odd, E + E is not possible. (2 + 2 = 4). When you (must) remove E + E, you are left with two integers. One is odd. The other is even.
So, one of the two integers must be even, and the other integer must be odd.
That is Answer C.
a = 3, b = 4
Even product? Yes. (3*4) = 12
Odd sum? Yes. 3+4 = 7. CORRECT
You can disprove the others.
A. The two integers are both odd.
a = 3, b = 5
Even product? No. 3*5 = 15
Odd sum? No. 3 + 5 = 8
REJECT
B. The two integers are both even.
a = 2, b = 4
Even product? Yes. 2*4 = 8
Odd sum? No. 2 + 4 = 6
REJECT
D. One of the integers is 1. The other can be odd.
From above Answer A, if both are odd, incorrect.
True, if a = 1 and b = 2, the conditions are satisfied. But if the other number is odd, conditions are not satisfied. One contrary example means the answer does not HAVE to be true. REJECT
E. The two integers are consecutive.
IF the two integers are consecutive, then they are odd and even, or vice versa, and they satisfy the prompt's conditions.
But the prompt just says "two integers." Those two integers need only be odd and even, not necessarily consecutive. They could be 1 and 200.
Answer C
Edited to correct a mistaken assumption, with help from @jaissonespidey