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09 Nov 2017, 23:26
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
69% (02:27) correct
31%
(02:25)
wrong
based on 80
sessions
History
Date
Time
Result
Not Attempted Yet
The figure above is formed by connecting perpendicular line segments that have lengths as shown. What is the length of the dashed line segment?
(A) 5
(B) 2√7
(C) 4√2
(D) √34
(E) √41
Attachment:
2017-11-07_0942.png [ 6.03 KiB | Viewed 3103 times ]
11 Nov 2017, 11:15
Kudos
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Bunuel
Attachment:
ttt.png [ 23.74 KiB | Viewed 2517 times ]
Connected perpendicular lines = all lines are parallel such that the distance between the two at any given point is the same.
To find lengths of sides of what turns out to be an isosceles right triangle
1. Extend right side of figure down - gray dotted line: whole side length = 7 (parallel to other side whose length = 7)
Part of that line = one side of a right triangle whose hypotenuse is the black dotted line
From the right side, extend a line horizontally until it meets the hypotenuse, to form the other side of the triangle.
See small labeled triangle.
2. Length of BC = (9 - 7) = 2
3. Length of AB = (5 - 3) = 2
4. Length of CD = (3 - 1) = 2
5. Length of DE = (7 -5) = 2
Each side of the right triangle = (2 + 2) = 4
Isosceles right triangles have side lengths in ratio \(x: x: x\sqrt{2}\)
\(x = 4\)
\(x\sqrt{2} = 4\sqrt{2}\)= hypotenuse = black dashed line
OR
\(4^2 + 4^2 = (hypotenuse)^2\)
\((16 + 16) = 32 = h^2\)
\(h = \sqrt{32}\)
\(h = \sqrt{16 * 2}= 4\sqrt{2}\) = black dashed line
black dashed line = \(4\sqrt{2}\)
Answer C
General Discussion
11 Nov 2017, 06:01
Kudos
Bookmarks
Bunuel
calculate the diagonal of the triangle formed by figure. then you will get answer 2 square root 4.
answer option c
