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16 Nov 2017, 22:57
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
89% (01:21) correct
11%
(02:36)
wrong
based on 55
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Not Attempted Yet
In the figure above, vertex R of square PQRS is the center of the circle. If QT = TR = 3, what is the area of the shaded region?
(A) 9 + 27π/4
(B) 9 + 27π
(C) 36 + 27π/4
(D) 36 + 9π
(E) 36 + 27π
Attachment:
2017-11-17_0948.png [ 6.48 KiB | Viewed 4347 times ]
17 Nov 2017, 00:35
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Area of shaded region = Area of square + 3/4 Area of the circle = 6^2+3/4*P*3^2=36 + 27/4*P
Answer C
Answer C
17 Nov 2017, 09:09
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Bunuel
Area of square is 6^2 = 36
Area of 3/4 th Circle is \(\frac{3π3^2}{4}\) = \(\frac{27π}{4}\)
So, Area of the total figure is \(36\) + \(\frac{27π}{4}\), answer will be (C)
