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Bunuel
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Abhishek009
Bunuel
The local bowling alley has three categories of bowlers; beginner, intermediate and expert. If there are 6 beginning bowlers for every 5 intermediate bowlers and 5 beginning bowlers for every expert bowler, what is the ratio of intermediate bowlers to all bowlers?

A. 30 : 61
B. 25 : 61
C. 25 : 54
D. 1 : 4
E. 1 : 3
Attachment:
Ratio.PNG
Total number of bowlers is 30+25+6 = 61

So, the ratio of intermediate bowlers to all bowlers is \(25:61\)

Answer will be (C)

Hi Abhishek,

Your calculation is correct, but your answer is wrong. :-)
The answer is B not C. I have marked that with RED text.
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Bunuel
The local bowling alley has three categories of bowlers; beginner, intermediate and expert. If there are 6 beginning bowlers for every 5 intermediate bowlers and 5 beginning bowlers for every expert bowler, what is the ratio of intermediate bowlers to all bowlers?

A. 30 : 61
B. 25 : 61
C. 25 : 54
D. 1 : 4
E. 1 : 3

\(Beginner=b;Intermediate=i;Expert=e\)

What is \(\frac{i}{(b+i+e)}?\)

\(6b=5i\), so \(\frac{i}{b}=\frac{5x}{6x}\) and \(e=5b\) so \(\frac{e}{b}=\frac{y}{5y}\)

Least common multiple of \(b=6x\) and \(b=5y\) is \(30\).

Multiples \(x\) and \(y\) will merge to \(z\).

New ratio \(i:b:e=[5x*(5):(30x=30y):y*(6)]=25z:30z:6z\)

Substitute values for \(i,b,e\): \(\frac{i}{(b+i+e)}=\frac{25z}{30z+25z+6z}=\frac{25z}{61z}=25:61\)

(B) is the answer.
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