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For a certain concert, 560 tickets were sold for a total of $2,150. 15 Feb 2018, 23:54
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83% (02:33) correct 17% (02:31) wrong based on 88 sessions

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For a certain concert, 560 tickets were sold for a total of $2,150. If an orchestra seat sold for twice the balcony seat price of $2.50, how many of the tickets sold were balcony seat tickets?

(A) 235

(B) 260

(C) 300

(D) 325

(E) 358
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B
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For a certain concert, 560 tickets were sold for a total of $2,150. 16 Feb 2018, 00:12
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Bunuel
For a certain concert, 560 tickets were sold for a total of $2,150. If an orchestra seat sold for twice the balcony seat price of $2.50, how many of the tickets sold were balcony seat tickets?

(A) 235

(B) 260

(C) 300

(D) 325

(E) 358
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560 tickets 2150

2.5x + 5y = 2150
x + y = 560

x+2y = 860
x+y = 560

y = 860-560 = 300

x=260


balcony seats (x) = 260
b
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For a certain concert, 560 tickets were sold for a total of $2,150. Updated on: 16 Feb 2018, 01:08
Originally posted by TaN1213 on 16 Feb 2018, 00:35.
Last edited by TaN1213 on 16 Feb 2018, 01:08, edited 2 times in total.
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For a certain concert, 560 tickets were sold for a total of $2,150. If an orchestra seat sold for twice the balcony seat price of $2.50, how many of the tickets sold were balcony seat tickets?

Let a= # of orchestra tickets
b = # of balcony tickets
A= price of orchestra tickets= 2 (price of balcony tickets) = 2*2.5 = 5

aA + bB = 2150
a+b =560

5a + 2.5(560-a) = 2150
a= 300
b= 260

-B-
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For a certain concert, 560 tickets were sold for a total of $2,150. 16 Feb 2018, 00:44
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TaN1213
For a certain concert, 560 tickets were sold for a total of $2,150. If an orchestra seat sold for twice the balcony seat price of $2.50, how many of the tickets sold were balcony seat tickets?

Let a= # of orchestra tickets
b = # of balcony tickets
A= price of orchestra tickets= 2 (price of balcony tickets) = 2*2.5 = 5

aA + bB = 2150
a+b =560

5a + 2.5(560-a) = 2150
a= 260
b= 300

-C-
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if the balcony seats were 300

300 x 2.5 + 260 x5 = 2050

it should be the other way around
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For a certain concert, 560 tickets were sold for a total of $2,150. 16 Feb 2018, 00:47
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Hatakekakashi
TaN1213
For a certain concert, 560 tickets were sold for a total of $2,150. If an orchestra seat sold for twice the balcony seat price of $2.50, how many of the tickets sold were balcony seat tickets?

Let a= # of orchestra tickets
b = # of balcony tickets
A= price of orchestra tickets= 2 (price of balcony tickets) = 2*2.5 = 5

aA + bB = 2150
a+b =560

5a + 2.5(560-a) = 2150
a= 260
b= 300

-C-

if the balcony seats were 300

300 x 2.5 + 260 x5 = 2050

it should be the other way around
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Thanks. I had this doubt. Will edit my post.
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For a certain concert, 560 tickets were sold for a total of $2,150. 16 Feb 2018, 01:08
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TaN1213
Hatakekakashi
TaN1213
For a certain concert, 560 tickets were sold for a total of $2,150. If an orchestra seat sold for twice the balcony seat price of $2.50, how many of the tickets sold were balcony seat tickets?

Let a= # of orchestra tickets
b = # of balcony tickets
A= price of orchestra tickets= 2 (price of balcony tickets) = 2*2.5 = 5

aA + bB = 2150
a+b =560

5a + 2.5(560-a) = 2150
a= 260
b= 300

-C-

if the balcony seats were 300

300 x 2.5 + 260 x5 = 2050

it should be the other way around

Thanks. I had this doubt. Will edit my post.
Show more

I felt the same and thus verified my answers
Do try this it helps
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For a certain concert, 560 tickets were sold for a total of $2,150. 21 Nov 2024, 23:50
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